The (small) challenge here is to determine what the LCD is. Since 11, 17 and 3 are all prime, we find the LCD by multiplying them together: 561.
Then 9/11= 459/561; 15/17 = 495/561; and 2/3 = 375/561.
Answer:
The base is 19.5.
Step-by-step explanation:
The given question is, "The perimeter of a rectangle is 58 and its base exceeds its width by 10, how long is the base?"
Perimeter = 58
Base, l = 10+b
The perimeter of a rectangle is :
P = 2(l+b)
58 = 2(10+b+b)
29 = (10+2b)
29-10 = 2b
19 = 2b
b = 9.5
Base, l = 10 + 9.5
= 19.5
Hence, the base is 19.5.
The perimeter of a rectangle is 2*L+2*W. Knowing that length is 99, we do 2*99 to get 198.Do 374-198, which is 176, we know that that is twice the length of the width. Therefore the width is 176/2, which is 88.
Answer: 224 cubic feet
Step-by-step explanation: If the base of the tank is 56 sq feet in<u> area </u> then the dimensions could be, (2,28) (4,14) (7,8) for example. However, it doesn't really matter. It's only important that the information we know is that it is area and there are two dimensions. Since volume is determined by base x width x height, we do 56 x 4. Or using one of the factored pairs that works, for example, 8 x 7 x 4 = 224.
Answer:
The present value of K is, 
Step-by-step explanation:
Hi
First of all, we need to construct an equation system, so
Then we equalize both of them so we can find 
To solve it we can multiply 
to obtain 
, then we have 
.
This leads to a third-grade polynomial 
, after computing this expression, we find only one real root 
.
Finally, we replace it in (1) or (2), let's do it in (1) 
