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3 years ago

Help plzz I will mark brainliestttt

Mathematics

1 answer:

Nadya [2.5K]3 years ago

8 0

The answer is .4 !!!!!!!!!!!!!

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1/(x+1) + 1/a(x+1) find the lcm

azamat

Answer:

See below.

Step-by-step explanation:

1/(x + 1) consists of 1 factor, 1/(x + 1)

1/[a(x + 1)] consists of two factors, 1/a and 1/(x + 1)

The LCM is 1/[a(x + 1)]

The LCD is a(x + 1)

5 0

3 years ago

The exponent indicates how many times the ......... is used as a factor

Dimas [21]

Base or base number
for example 2^3 = 2 * 2 * 2 or x^2 = x * x

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3 years ago

WILL GIVE BRAINLIEST 10 POINTS Select all ordered pairs that satisfy the function y= -1/2x + 4

Ulleksa [173]

B I think but i could be totally wrong

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3 years ago

let X represent the amount of time till the next student will arriv ein the library partking lot at the university. If we know t

AlekseyPX

Answer:

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

Mean of 4 minutes

This means that $m = 4, \mu = \frac{1}{4} = 0.25$

Find the probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot:

This is:

$P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2)$

In which

$P(X \leq 132) = 1 - e^{-0.25*132} = 1$

$P(X \leq 2) = 1 - e^{-0.25*2} = 0.393469$

$P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2) = 1 - 0.393469 = 0.606531$

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

4 0

3 years ago

Hi. Sorry this is bad quality. <br><br> What is the slope of the line on the graph?

d1i1m1o1n [39]

Slope (m) =0

θ =180°

distance (d) =15

ΔX =15

ΔY =0

5 0

3 years ago