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2 years ago

Find the area of the shape below?

Mathematics

2 answers:

masya89 [10]2 years ago

4 0

Answer:

8,910

Step-by-step explanation:

i just multiplied all the sides

and i got 8,910

gogolik [260]2 years ago

4 0

Answer:

105 cm²

Step-by-step explanation:

The shape is composed of a rectangle and a triangle on the right side

area of rectangle = 15 × 6 = 90 cm²

The triangle has dimensions , base = (15 - 9) = 6 cm and height = (11 - 6) = 5 cm

area of triangle = $\frac{1}{2}$ × 6 × 5 = 3 × 5 = 15 cm²

Total area = 90 + 15 = 105 cm²

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traingle abc is an isosceles right triangle with the measure of angle a equal to 90 degrees. the length of segment ac is 6 cm. w

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Isosceles right triangles are half squares, and if the length of one side is 6cm, that is the length of the other side since both segments are equal. Take the formula to find the area of a square (base times height), apply the side measurement of the triangle (6cm) and divide it in half to find the area of half of it (therefore, finding the area of the isosceles triangle.)

(6x6) / 2
6x6 = 36
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3 years ago

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Ierofanga [76]

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So you have

$\displaystyle\int_0^2\frac{x^2+x+1}{(x+1)^2(x+2)}\,\mathrm dx=-2\int_0^2\frac x{(x+1)^2}\,\mathrm dx-\int_0^2\frac{\mathrm dx}{(x+1)^2}+3\int_0^2\frac{\mathrm dx}{x+2}$
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where in the first integral we substitute $x\mapsto x+1$ .

$=\displaystyle-2\int_1^3\left(\frac1x-\frac1{x^2}\right)\,\mathrm dx-\frac1{1+x}\bigg|_{x=0}^{x=2}+3\ln|x+2|\bigg|_{x=0}^{x=2}$
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3 years ago

Write an absolute value equation that represents these heights 10 and 15

djverab [1.8K]

Answer:

An equation for the absolute value that represents the midpoint of 10 and 15 would be (10 + 15)/2 = 12.5

6 0

3 years ago