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2 years ago

Write the number in expanded form for the significant digits

2 answers:

7 0

Expanded form:
1. 117.00= 100+ 10+ 7
2. 20.018 = 20+ 0.01+ 0.008
3. 13.265 = 10+ 3+ 0.2+ 0.06+ 0.005
4. 3.4000 = 3+ 0.4
5. 0.8100 = 0.8+ 0.01

Ymorist [56]2 years ago

3 0

117.000 = 117 x 10^3

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3 years ago

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jeni works from 8:00-3:15 three days in a row, only taking a half-hour unpaid lunch break each day. if she is paid $15 per hour,

enyata [817]

Jeni gets paid $ 303.75 for 3 days

Solution:

Given that,

Jeni works from 8:00-3:15 three days in a row

Find the number of hours between 8 : 00 to 3 : 15

8 : 00 to 3 : 15 = 7 hours 15 minutes

She is taking half-hour unpaid lunch break each day

7 hours 15 minutes - half an hour = 6 hours 45 minutes

So, she works for 6 hours 45 minutes for each three days

$6\ hours\ 45\ minutes = 6 + \frac{45}{60} = 6 + 0.75 = 6.75\ hours$

She is paid $15 per hour

Therefore, total earnings for 3 days is given as:

$Total\ Earnings = 3 \times 15 \times 6.75\\\\Total\ Earnings = 303.75$

Thus she gets paid $ 303.75 for 3 days

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3 years ago

What’s the area and perimeter for this problem?

neonofarm [45]

Answer:

area:1.9×0.75÷2

perimeter:2+0.75+2.25

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2 years ago

What is the equation in standard form of a parabola that models the values in the table

shusha [124]

Answer:

Y=4x^2-3x+5

Step-by-step explanation:

For the standard form equation to model the values in the table, each value of x in the table should give the matching the y value when substituted into the equation. We will test each equation:

$Y=-4x^2+3x+5$ for (-1,12)

$Y=-4(-1)^2+3(-1)+5=-4(1)+-3+5=-4+-3+5=-2\\$

This does not give 12 as the answer and is not a solution.

$Y=-4x^2-3x+5$ for (-1,12)

$Y=-4(-1)^2-3(-1)+5=-4(1)+3+5=-4+3+5=4\\$

This does not give 12 as the answer and is not a solution.

$Y=3x^2-4x+5$ for (-1,12)

$Y=3(-1)^2-4(-1)+5=3(1)+4+5=3+4+5=12\\$

This does give 12 as the answer and is a possible solution.

We now try (2,15).

$Y=3(2)^2-4(2)+5=3(4)-8+5=12-8+5=9\\$

This does not give 15 as the answer and is not a possible solution.

$Y=4x^2-3x+5$ for (-1,12)

$Y=4(-1)^2-3(-1)+5=4(1)+3+5=4+3+5=12\\$

This does not give 12 as the answer and is not a solution.

We now try (2,15).

$Y=4(2)^2-3(2)+5=4(4)-6+5=16-6+5=15\\$

This does give 15 as the answer and is a solution.

This is the standard form of the equation.

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3 years ago

What is the inequality -24<3(3x-2)<30

4vir4ik [10]

Answer:

− 2 < x < 4

Step-by-step explanation:

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