Answer:
total area = 193.31 m²
Step-by-step explanation:
rectangle area = 7 x 15 = 105 m²
semi circle area = (3.14)(7.5²)/2 = 88.31 m²
total area = 105 m² + 88.31 m² = 193.31 m²
Answer:
B
Step-by-step explanation:
Answer:
3.84% of months would have a maximum temperature of 34 degrees or higher
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 29.9, \sigma = 2.31](https://tex.z-dn.net/?f=%5Cmu%20%3D%2029.9%2C%20%5Csigma%20%3D%202.31)
What percentage of months would have a maximum temperature of 34 degrees or higher?
This is 1 subtracted by the pvalue of Z when X = 34. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{34 - 29.9}{2.31}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B34%20-%2029.9%7D%7B2.31%7D)
![Z = 1.77](https://tex.z-dn.net/?f=Z%20%3D%201.77)
has a pvalue of 0.9616
1 - 0.9616 = 0.0384
3.84% of months would have a maximum temperature of 34 degrees or higher
X=5, y=-4
(5,-4)
do you need the work?
Answer:
126 inches
Step-by-step explanation:
If your drawing is on a 1 : 40 scale, to find the scale's height, divide the ride's height by 40.
420 / 40 = 10.5
So the drawing will be 10.5 feet tall.
To convert 10.5 feet to inches, multiply it by 12.
10.5 * 12 = 126 inches