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Vinvika [58]
2 years ago
6

If both cars in Exercise 62 are on one side of the plane and if the angle of depression to one car is 38∘ and that to the other

car is 52∘, how far apart are the cars?

Mathematics
1 answer:
Sati [7]2 years ago
7 0

The two cars lying on one side of the plane are 50 meters apart.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

let us assume that the height is 100 m. Let d represent the horizontal distance. For depression of 38°, Ф = 90 - 38 = 52°, hence:

tan(52°) = d / 100

d = 128 m

For depression of 52°, Ф = 90 - 52 = 38°, hence:

tan(38°) = d / 100

d = 78 m

Distance apart = 128 - 78 = 50 m.

The two cars lying on one side of the plane are 50 meters apart.

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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Step-by-step explanation:

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Plug in the function

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3 years ago
If George is 33 1/3% richer than Pete, than Pete is what percent poorer than George?
OleMash [197]

Answer:

25%

Step-by-step explanation:

George is 33\frac{1}{3}% (\frac{100}{3}%) richer than Pete. Let Pete's percentage of wealth be 100%.

Thus George percentage of wealth = 100% + \frac{100}{3}%

                                                           = \frac{400}{3}%

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Pete's percent poorer than George can be determined by;

                                                           = (\frac{100}{3}) ÷ (\frac{400}{3} ) × 100

                                                           = (\frac{100}{3}) × \frac{3}{400} ×100

                                                           = 0.25 × 100

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Pete is 25% poorer than George.

3 0
3 years ago
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