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stich3 [128]
3 years ago
15

The length of needles produced by a machine has standard deviation of 0.04 inches. Assuming that the distribution is normal, how

large a sample is needed to determine with a precision of ±0.005 inches the mean length of the produced needles to 98% confidence?
Mathematics
1 answer:
Lana71 [14]3 years ago
3 0

Answer:

The sample size is  n  = 87

Step-by-step explanation:

From the question we are told that

      The standard deviation is  \sigma  =  0.04 \  inches

       The  precision is d =  \pm  0.005 \ inches

        The confidence level is C =98%

Generally the sample size is mathematically represented as  

        n  =  \frac{ Z_{\frac{\alpha }{2} } ^2*  \alpha^2 }{d^2}

Where  \alpha  is the level of significance which is mathematically evaluated as

        \alpha  =  100 - 98

        \alpha  =  2%

        \alpha  = 0.02

and  Z_{\frac{\alpha }{2} } is the critical value of \alpha which is obtained from the normal distribution table as  2.326

  substituting values

         n  =  \frac{2.326 ^2*  0.02^2 }{0.005^2}

        n  = 87

   

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Answer:

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Step-by-step explanation:

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We can then look and see that g(1) = 4 as shown by the point given to us on the graph.

To find the right answer we can find g(1) for options C & D and whichever one matches the point on the graph is our correct answer. e

Option C:

once we plug in 1 for x, our equation looks like

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1^2 = 1, and 4(1) = 4,

so g(1) = 4. and our point is (1,4).

This is the same as the graph so this is the CORRECT answer.

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Option D:

once we plug in 1 for x, our equation looks like

16(1)^2

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Step-by-step explanation:

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For a better understanding of the solution provided here please find the diagram attached.

Please note that in coordinate geometry, the coordinates of the midpoint of a line segment is always the average of the coordinates of the endpoints of that line segment.

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