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3241004551 [841]
2 years ago
12

If 0° < θ < 90° or 180° < θ < 270°, explain why sin 2θ is always positive.

Mathematics
1 answer:
Angelina_Jolie [31]2 years ago
8 0

Using a trigonometric identity, since in the first quadrant and in the third quadrant the sine and the cosine have the same sign, \sin{2\theta} is always positive.

<h3>What is the trigonometric identity for sin 2θ?</h3>

It is given by:

\sin{2\theta} = 2\sin{\theta}\cos{\theta}

In the first quadrant(0° < θ < 90°) and in the third(180° < θ < 270°), the sine and the cosine have the same sign, hence the multiplication is positive and \sin{2\theta} is always positive.

More can be learned about trigonometric identities at brainly.com/question/24496175

#SPJ1

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Simplifying

(0.75x + 6) + -1(2.5x + -1.9) = 0


Reorder the terms:

(6 + 0.75x) + -1(2.5x + -1.9) = 0


Remove parenthesis around (6 + 0.75x)

6 + 0.75x + -1(2.5x + -1.9) = 0


Reorder the terms:

6 + 0.75x + -1(-1.9 + 2.5x) = 0

6 + 0.75x + (-1.9 * -1 + 2.5x * -1) = 0

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Reorder the terms:

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Combine like terms: 6 + 1.9 = 7.9

7.9 + 0.75x + -2.5x = 0


Combine like terms: 0.75x + -2.5x = -1.75x

7.9 + -1.75x = 0


Solving

7.9 + -1.75x = 0


Solving for variable 'x'.


Move all terms containing x to the left, all other terms to the right.


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7.9 + -7.9 + -1.75x = 0 + -7.9


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Combine like terms: 0 + -7.9 = -7.9

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Simplifying

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