Answer:
a.
-6a²/ b
b.
5y³
Step-by-step explanation:
a
-6a²b⁻¹
-6a²/ b
b.
5/ y⁻³
5 / 1/ y³
5 * y³/1
5y³
Answer:
(a) The solutions are: 
(b) The solutions are: 
(c) The solutions are: 
(d) The solutions are: 
(e) The solutions are: 
(f) The solutions are: 
(g) The solutions are: 
(h) The solutions are: 
Step-by-step explanation:
To find the solutions of these quadratic equations you must:
(a) For 





The solutions are: 
(b) For 

The solutions are: 
(c) For 

The solutions are: 
(d) For 


For a quadratic equation of the form
the solutions are:



The solutions are: 
(e) For 




The solutions are: 
(f) For 


The solutions are: 
(g) For 

Using the Zero Factor Theorem: = 0 if and only if = 0 or = 0

The solutions are: 
(h) For 

Using the Zero Factor Theorem: = 0 if and only if = 0 or = 0

The solutions are: 
Sorry dont know, any thing else you need help with?
About 24 hours per 1 day
8/24=1/3
Every time the x goes up 1 the y goes up by 3