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3 years ago

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Red Bull is the most popular energy drink in sales in the United States. Red Bull GmbH (the parent company) has observed that da

ily sales are normally distributed with an average of 6,205,195 drinks sold with a standard deviation of 9,120.32. What is the probability that on a given day below 6,214,323 drinks are sold

1 answer:

oee [108]3 years ago

8 0

Answer:

The probability that on a given day below 6,214,323 drinks are sold is 0.8413.

Step-by-step explanation:

The provided information are:

Population mean $(\mu)$ = 6,205,195

Population standard deviation $(\sigma)$ = 9,120.32

Consider, <em>X</em> be the random variable that represents the number of drinks that are sold on a given that is normally distributed with the mean = 6,205,195 and standard deviation = 9,120.32.

The probability that on a given day below 6,214,323 drinks are sold can be calculated as:

$P(X$

It must be noted that <em>P</em>(<em>Z</em> < 1.0008) = 0.8413 has been calculated using the standard normal table.

Hence, the required probability is 0.8413.

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Answer:

There are two numbers {1,2} which is less than 3. so, required probability P(E) = 2/6 = 1/3.

Step-by-step explanation:

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3 years ago

P is the midpoint of DE¯¯¯¯¯DE¯ , DP=3x+2DP=3x+2, and DE=10x−12DE=10x−12. What is the length of DP¯¯¯¯¯DP¯ ?

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3 years ago

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The circumference of a sphere was measured to be 80 cm with a possible error of 0.5 cm. A) Use differentials to estimate the max

siniylev [52]

Answer:

A) The maximum error in the calculated surface area: $25cm^2$

Relative error: $0.013$

B) The maximum error in the calculated volume: $162cm^2$

Relative error: $0.019$

Step-by-step explanation:

A) The formula for the surface area is:

$A=4\pi r^2$

The measured value is the circumference which is equal to:

$C=2\pi r$

then the radius is:

$r=\frac{C}{2\pi}$

Substituting in the formula of the surface:

$A=4\pi(\frac{C}{2\pi})^2\\A=4\pi(\frac{C^2}{4\pi^2})\\A=\frac{C^2}{\pi}$

Using the formula to calculate the error:

$dy=f'(x)dx$

Where $x$ is the variable measured and $y$ is a function of $x$ ( $y=f(x)$ ).

$dA=f'(C)dC\\dA=\frac{2C^{(2-1)}}{\pi}dC\\dA=\frac{2C}{\pi}dC$

We have C=80cm and dC=0.5cm

$dA=\frac{2C}{\pi}dC\\dA=\frac{2(80)}{\pi}(0.5)\\dA=\frac{160}{\pi}(0.5)\\dA=50.9296(0.5)\\dA=25.4648\approx25cm^2$

The relative error is the maximum error divide by the total area. The total area is: $A=\frac{C^2}{\pi}=\frac{(80)^2}{\pi}=\frac{6400}{\pi}=2037.1833cm^2$

$\frac{dA}{A}=\frac{25.4648}{2037.1833} =0.0125\approx0.013$

B) The formula for the volume is:

$V=\frac{4}{3} \pi r^3$

Using $r=\frac{C}{2\pi}$

$V=\frac{4}{3} \pi r^3\\V=\frac{4}{3} \pi (\frac{C}{2\pi})^3\\V=\frac{4}{3} \pi (\frac{C^3}{8\pi^3})\\V=\frac{1}{3}(\frac{C^3}{2\pi^2})\\V=\frac{C^3}{6\pi^2}$

The maximum error is:

$dV=\frac{3C^{3-1}}{6\pi^2}dC\\dV=\frac{C^{2}}{2\pi^2}dC\\dV=\frac{(80)^{2}}{2\pi^2}(0.5)\\dV=\frac{6400}{2\pi^2}(0.5)\\dV=\frac{6400}{2\pi^2}(0.5)\\dV=(324.2278)(0.5)\\dV=162.1139\approx162cm^2$

The calculated volume is:

$V=\frac{C^3}{6\pi^2}\\V=\frac{(80)^3}{6\pi^2}\\V=\frac{512000}{6\pi^2}\\V=8646.0743$

The relative error is:

$\frac{dV}{V}=\frac{162.1139}{8646.0743}=0.0188\approx0.019$

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lapo4ka [179]

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2 years ago

Bryan sells cars. He makes a salary of $500 a week, plus $150 for every car he sells. This week, he wants to make at least $2000

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If Bryan wants to make $2000 dollars then he needs to solve this equation:

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3 years ago

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