<em>Greetings from Brasil...</em>
In a trigonometric function
F(X) = ±UD ± A.COS(Px + LR)
UD - move the graph to Up or Down (+ = up | - = down)
A - amplitude
P - period (period = 2π/P)
LR - move the graph to Left or Right (+ = left | - = right)
So:
A) F(X) = COS(X + 1)
standard cosine graph with 1 unit shift to the left
B) F(X) = COS(X) - 1 = -1 + COS(X)
standard cosine graph with 1 unit down
C) F(X) = COS(X - 1)
standard cosine graph with shift 1 unit to the right
D) F(X) = SEN(X - 1)
standard Sine graph with shift 1 unit to the right
Observing the graph we notice the sine function shifted 1 unit to the right, then
<h3>Option D</h3>
<em>(cosine star the curve in X and Y = zero. sine start the curve in Y = 1)</em>
hopefully this will help ( ;
Answer:
2/5 or 40%
Step-by-step explanation:
.40 is 40 hundredths or 40/100
40/100 can be reduced to 20/50 and reduced again to 10/25 and one more time to 2/5
Percentages are fractions out of 100 so 40/100 would be 40%.
Answer:
912m
Step-by-step explanation:
There are two triangles.
The height of the triangles are 16m and the base is 12m.
Multiply 12(16)/2 to get the area of the triangle.
The area of the triangle is 96m.
Multiply 96 by 2 to get 192.
There are three rectangles.
Height is 20m and the base is 12m
20(12) is 240. Then, multiply by three.
240(3) is 720.
Add 192 and 720 to get 912m.
Hope this helps! Comment if I did something wrong.
Answer:
Step-by-step explanation:
quadratic equation: ax² + bx + c =0
x' = [-b+√(b²-4ac)]/2a and x" = [-b-√(b²-4ac)]/2a
6 = x² – 10x ; x² - 10x -6 =0
(a=1, b= - 10 and c = - 6
x' = [10+√(10²+4(1)(-6)]/2(1) and x" = [10-√(10²+4(1)(-6)]/2(1)
x' =5+√31 and x' = 5-√31
