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Neko [114]
3 years ago
12

I need help please.

Mathematics
1 answer:
algol [13]3 years ago
6 0

Answer:

x-9

Step-by-step explanation:

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The graph of a linear function has a slope of 1/4 and passes through the point (1,3). What is the y-intercept of the function?
Vikki [24]

Answer:

B

Step-by-step explanation:

In slope intercept form, y = mx + b, the m is the slope, the b is the y intercept, and x and y can be subbed in from the point you are given of (1, 3).  We are told the slope, so everything we have fills in like this:

3=\frac{1}{4}(1)+b

Now we just need to solve for b:

3-\frac{1}{4}=b and

\frac{12}{4}-\frac{1}{4}=b so

b=\frac{11}{4}

8 0
3 years ago
Find the slope of
Anon25 [30]

Answer:

(8,-9)

Step-by-step explanation:

using the principle of vectors, you match each number to their coordinates and add them

so we have (7+1,-12+3)

which is equal to (8,-9)

8 0
2 years ago
Read 2 more answers
HELP PICTURE IS SHOWN
scoray [572]
The answer is letteer C. You just have to multiply 9 and pi
8 0
3 years ago
Read 2 more answers
621/87 can anybody help me
Ilia_Sergeevich [38]

Answer:

621/87=7.13793103448

Step-by-step explanation:

I divided it and got this answer

5 0
3 years ago
Read 2 more answers
A local car dealer claims that 25% of all cars in San Francisco are blue. You take a random sample of 600 cars in San Francisco
sammy [17]

Answer:

No, we can't reject the dealer's claim with a significance level of 0.05.

Step-by-step explanation:

We are given that a local car dealer claims that 25% of all cars in San Francisco are blue.

You take a random sample of 600 cars in San Francisco and find that 141 are blue.

<u><em>Let p = proportion of all cars in San Francisco who are blue</em></u>

SO, Null Hypothesis, H_0 : p = 25%   {means that 25% of all cars in San Francisco are blue}

Alternate Hypothesis, H_A : p \neq 25%   {means that % of all cars in San Francisco who are blue is different from 25%}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of 600 cars in San Francisco who are blue =   \frac{141}{600} = 0.235

            n = sample of cars = 600

So, <u><em>test statistics</em></u>  =  \frac{0.235-0.25}{{\sqrt{\frac{0.235(1-0.235)}{600} } } } }

                               =  -0.866

<em>Now at 0.05 significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics lies within the range of critical values of z so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>

Therefore, we conclude that 25% of all cars in San Francisco are blue which means the dealer's claim was correct.

4 0
3 years ago
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