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Kisachek [45]
2 years ago
11

Which expression is equivalent to startfraction 3 x superscript negative 6 baseline y superscript negative 3 baseline over 15 x

squared y superscript 10 baseline endfraction? assume x not-equals 0, y not-equals 0.
Mathematics
1 answer:
Sunny_sXe [5.5K]2 years ago
8 0

The correct expression is 1 Over 5 x Superscript minus 8 Baseline y Superscript minus 13 Baseline endFraction.

Given expression (3x)^-6*y^-3/ 15x^2*y^10

Lets simplify the equation:

= > (3x)^-6*y^-3/ 15x^2*y^10\\=1/5 x^-8*y^-13

Expression:

An expression is a sentence with a minimum of two numbers or variables and at least one math operation. This math operation can be addition, subtraction, multiplication, or division. The structure of an expression is: Expression is (Number/Variable, Math Operator, Number/Variable)

Hence the correct expression is 1 Over 5 x Superscript minus 8 Baseline y Superscript minus 13 Baseline EndFraction.

Learn more about Expression on:

brainly.com/question/1280754

#SPJ4

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A cell tower is located at and transmits a circular signal that covers three major cities. The three cities are located on the c
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Answer:

(x+8)^2 +(y-4)^2 = 25

Step-by-step explanation:

Assuming this complete problem: "A cell tower is located at (-8, 4) and transmits a circular signal that covers three major cities. The three cities are located on the circle and have the following coordinates: G (-4, 7), H (-13, 4), and I (-8, -1). Find the equation of the circle"

For this case the generla equation for the circle is given by:

(x-h)^2 +(y-k)^2 = r^2

From the info we know that the tower is located at (-8, 4) so then h = -8 and k = 4, so then we need to find the radius. So we have the equation like this:(x+8)^2 +(y-4)^2 = r^2

If the 3 points are on the circle then satisfy the equation. We can use the first point (-4,7) and if we replace we can find the value for r^2

(-4+8)^2 +(7-4)^2 =25= r^2

So then r = \sqrt{25}=5

And if we replace the second point we got this:

(-13+8)^2 +(4-4)^2 = 25 =r^2

And for the third point we have:

(-8+8)^2 +(-1-4)^2 = 25 =r^2

And we got the same result.

So then our final equation is given:

(x+8)^2 +(y-4)^2 = 25

4 0
4 years ago
Figure ABCD is a rhombus where the m∠ABC = 84 and m∠ABE = 3x − 6. Solve for x. Rhombus ABCD with diagonals AC and BD and point E
bazaltina [42]

Answer:

<u> x = 16</u>

Step-by-step explanation:

See the attched figure

We should know that, one of the properties of the rhombus is the diagonals bisect the angles of the rhombus.

Given:

m∠ABC = 84  and m∠ABE = 3x − 6

So, m∠ABE = 0.5 * m∠ABC = 0.5 * 84 = 42

∴ 3x - 6 = 42

Solve for x

3x = 42 + 6 = 48

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<u>∴ x = 16</u>

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                                hope this helps:)

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Find the inverse of the function y = x2 – 12
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Answer: y=\sqrt{x+12}

Step-by-step explanation:

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You switch the y and x variables:

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