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Nostrana [21]
3 years ago
12

Solve the equation by completing the square m^2+6m-77=-5

Mathematics
1 answer:
Grace [21]3 years ago
6 0
Maybe you thought about this:
m^2+6m-77+5=0 => m^2+6m-72=0 => m^2+ 2*3*m+3^2-3^2-72=0
=> m^2+2*3*x+3^2= (m+3)^2 this is the complete square of the binomial, we will still keep it =>
(m+3)^2 -9 -72=0 => (m+3)^2 - 81 = 0 => (m+3)^2 - 9^2 = 0
Now we got the difference squares, it mean a^2 - b^2 = (a-b) (a+b)
In according to this => (m+3-9) (m+3+9) = 0 =>
(m-6) (m+12)=0 => m-6=0 or m+12=0 => m1=6 or m2= -12 !!!!
Are you satisfied with this solution?

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Following that logic you can express the men of any level of his organization as 10^n, where n is the level. Some examples:

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Level 2: 10^2 = 100 Each of the 10 men in level 1 are in charge of 10 men in the level 2 (10 * 10 = 100)

(a) if the lowerst level of the organization has 10,000 soldiers, then the lowest level is:

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The total number of men under him is:

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(b) In this case the lowest level has 5763, you have a 1 leader for every 10 soldiers, then the leaders needed for the lowest level is:

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These 577 leaders also have their own leaders for every 10:

577/10 = 57.7 = 58 leaders

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58 / 10 = 5.8 = 6

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3 years ago
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