Answer:
Consecutive odd integers are 19 , 21 & 23
Step-by-step explanation:
Let the first 3 consecutive odd intergers be x , (x + 2) and (x + 4).
According to the question,
Eliminating 2x from both the sides,
So, the consecutive odd integers are = 19 , 21 & 23.
Step-by-step explanation:
4^5 (-2)^9/4^8 (-2)^3
= 4^(5 - 8) (-2^(9 - 3))
= 4^-3 (-2^6)
= (-2)^6/4^3
1). (-2)^a/4^b
a = 6, b = 3
2). c/d
c = -2, d = 4
Answer:
Not enough info for a valid answer.
Step-by-step explanation:
here we have to find the quotient of '(16t^2-4)/(8t+4)'
now we can write 16t^2 - 4 as (4t)^2 - (2)^2
the above expression is equal to (4t + 2)(4t - 2)
there is another expression (8t + 4)
the expression can also be written as 2(4t + 2)
now we have to divide both the expressions
by dividing both the expressions we would get (4t + 2)(4t - 2)/2(4t + 2)
therefore the quotient is (4t - 2)/2
the expression comes out to be (2t - 1)
