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zloy xaker [14]
2 years ago
9

I need help with this slope

Mathematics
1 answer:
Alex73 [517]2 years ago
8 0

Answer:

Step-by-step explanation:

First, the y-intercept is -3 so from -3 the slop to the next point is 4/1.

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Thank you for helping :D
padilas [110]
1. I chose Volleyball, which has only 2 kids. Football has 9 kids. So to find how many more kids prefer Football over Volleyball we subtract the two.

9-2= 7

2. The least popular sport is Volleyball, which again is 2.
And soccer has 7 kids who prefer Soccer over any other sport.

So it’s the same process, 7-2= 5
7 0
3 years ago
Tarea resuelta de matemática semana 32 3ro de secundaria.
erastova [34]

Answer:

Solved math homework week 32 3rd of secondary school.

Felicidades

Step-by-step explanation:

5 0
2 years ago
How do you find the area of the shaded region
Amiraneli [1.4K]

well, first off, let's notice that we have a trapezoid with a rectangle inside it, so the rectangle is really "using up" area that the trapezoid already has.

now, if we just get the area of the trapezoid, and then the area of the rectangle alone, and then subtract that area of the rectangle, the rectangle will in effect be making a hole inside the trapezoid's area, and what's leftover, is the shaded section, that part the hole is not touching.

\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h&=height\\ a,b&=\stackrel{parallel~sides}{bases} \\\cline{1-2} h&=8\\ a&=16\\ b&=8 \end{cases}\implies A=\cfrac{8(16+8)}{2}\implies A=96 \\\\\\ \stackrel{\textit{area of the rectangle}}{(5\cdot 3)\implies 15}~\hfill \stackrel{~\hfill \textit{shaded area}}{\stackrel{\textit{trapezoid}}{96}~~ - ~~\stackrel{\textit{rectangle}}{15}~~ = ~~81}

3 0
3 years ago
Can any one help me if you do you will recive 30 points please help :,(
kodGreya [7K]
1. so since we assume that CF is a straight line that means that the angle CAF is 180 angle CAD is 90 and FAE is 65 so 180-(65+90)=DAE=25

2. so since angle QPR= angle TPS (both are signified by f) and we assume that QT is straight so then QPT=180
180-154=2f=26
angle f=13
QPR=13

3. so we assume that BG is straight so it is 180
we add up the known angles (BQD+DQE+FQG=10+103+12=125) 180-125=DQC+EQF=55=2x+3x=5x
5x=55
x=11
CQD=2x=22
EQF=3x=33

4. we know that x=x and the whole is 360 so
x+x+x+x+71+71+71+71=360=4x+284=360
4x=76
x=19

8. so we assume that EF and CD are straight lines so EQD=CQF so 155=56+3x so
99=3x
CQG=99

9. so adjacent and the ratio is 4:5 so a line is 180 so 4+5=9 180/9=20  20*4=80 20*5=100 4:5 =80:100

a. 80 and 100
b. you should be able to do this

10. so on a line is 180
a. 3:4:5  3+4+5=12  180/12=15
3*15=45  4*15=60  5*15=75
3:4:5 =45:60:75
the angles are 45 60 75

b. you should be able to do this from my work

5 0
3 years ago
Hi good night all :) ✨
maw [93]

Answer:

Hello good morning

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
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