Using the normal distribution, it is found that 0.0764 = 7.64% of teenagers who will have waist sizes greater than 31 inches.
<h3>Normal Probability Distribution</h3>
In a normal distribution with mean 
and standard deviation 
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem:
- The mean is of
.
- The standard deviation is of
.
The proportion of teenagers who will have waist sizes greater than 31 inches is <u>1 subtracted by the p-value of Z when X = 31</u>, hence:
has a p-value of 0.9236.
1 - 0.9236 = 0.0764.
0.0764 = 7.64% of teenagers who will have waist sizes greater than 31 inches.
More can be learned about the normal distribution at brainly.com/question/24663213
The mole fraction of the non-volatile solute in the solution is 0.13.
<h3>Mole fraction of solute </h3>
Using law of vapor pressure formula
Mole fraction of the non-volatile solute=Vapor pressure of the pure acetone-Vapor pressure of the solution /Vapor pressure of the pure acetone
Where:
Vapor pressure of the pure solvent (acetone) =266 torr
Vapor pressure of the solution =232torr
Mole fraction of solute = ?
Let plug in the formula
Mole fraction of the non-volatile solute=266-232/266
Mole fraction of the non-volatile solute=34/266
Mole fraction of the non-volatile solute=0.127
Mole fraction of the non-volatile solute=0.13 (Approximately)
Inconclusion the mole fraction of the non-volatile solute in the solution is 0.13.
Learn more about mole fraction of the non-volatile solute here: brainly.com/question/14114576
Answer:
Explanation:
cv= standard deviation/ mean
40/3
13.33
