What the sample suggests is that; the mean body temperature couldvery possibly bevery possibly be 98.6 °F.
<h3>What is the Confidence Interval?</h3>
For a 99% Confidence Interval and DF = 103 - 1 = 102, the value of z = 2.33.
The formula for confidence interval is;
CI = x⁻ ± z(σ/√n))
We are given;
Sample mean; x⁻ = 98.9
standard deviation; σ = 0.67
sample size; n = 103
Thus the confidence Interval is;
CI = [98.9 - 2.33(0.67/√103)], [98.9 + 2.33(0.67/√103)]
CI = (98.9 - 0.154, 98.5 + 0.154)
CI = (98.36, 98.64)
Thus, 98.6 is contained within the 99% CI,and so we can conclude that the the mean body temperature could very possibly bevery possibly be 98.6 °F.
Read more about Confidence Interval at; brainly.com/question/17097944
ph--10.55 because
pH + pOH = 14 ;
Given: pOH = 3.45 ; Solve for pH ;
pH + 3.45 = 14 ;
Subtract "3.45" from each side of the equation:
pH + 3.45 - 3.45 = 14 - 3.45 ;
pH = 10.55
Answer:
I believe it's B - Second-Degree Burns
Explanation:
A first degree burn would be like keeping your finger over a flame for a little too long, it'll cause red skin and some pain, but not the white boarder. Third degree burns would be like holding onto metal left in burning temperatures, touching lava, it'll burn all the way down to the fat tissue, causing emese pain. Fourth degree burns are horrible, the skin turns black, it burns past the fat tissue, no way it would cause only "some" pain
The answer is D. Analyse the value of a borrowers home and cars to be used as collateral for a loan.
The Treaty of Paris.. I think that would be the answer.
