Answer:y =ax² + bx +c
1) Point (0,7)
7 = a*0² +b*0 +c
c = 7
y=ax² + bx + 7
2) Point (1,4)
4=a*1² + b*1 + 7, ----> 4 = a +b + 7, ------> a+b= - 3
3) Point (2, 5)
5=a*2² + b*2 + 7, ----> 5=4a+2b +7,---> -2=4a+2b, ----> -1=2a + b
4) a+b= - 3, ----> b= -3 - a (substitute in the second equation)
2a+b= -1
2a - 3 - a = -1, ----> a - 3 = -1, a =2
5) a+b= - 3
2 + b = -3
b = -5
y=2x² - 5x + 7
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Step-by-step explanation:
Answer:
22
Step-by-step explanation:
44 * .5 (or 1/2) = 22
22+22=44
i hope this helps! :D
Answer:
462
Step-by-step explanation:
C(11, 5)
= 11!/(11-5! * 5!)
= 462
I believe that f(x) = 3(x-1). From the distance between the f(x) values you can infer that the factor in front of x must be 3. Then for x=0 the value is -3. So f(x) = 3x - 3 or 3(x-1).
Answer:
1. -5
2.10
3.1
4.-10
5.18
6.10
7.4
8.-1
9.1
10.89
11.3
12.10
13.13
14.-2
15.-7
16.14
17.-8
18.-6
19.-8
20.-22
Step-by-step explanation: