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Paul [167]
2 years ago
14

Identify the vertices of the feasible region and use them to find the maximum and/or minimum value for the given linear programm

ing constraints.
System of Linear Programming:

z=−3x+5y

x+y≥−2

3x−y≤2

x−y≥−4

Maximum value of z:

Minimum value of z
Mathematics
1 answer:
Ghella [55]2 years ago
4 0

The maximum value of the objective function is 26 and the minimum is -10

<h3>How to determine the maximum and the minimum values?</h3>

The objective function is given as:

z=−3x+5y

The constraints are

x+y≥−2

3x−y≤2

x−y≥−4

Start by plotting the constraints on a graph (see attachment)

From the attached graph, the vertices of the feasible region are

(3, 7), (0, -2), (-3, 1)

Substitute these values in the objective function

So, we have

z= −3 * 3 + 5 * 7 = 26

z= −3 * 0 + 5 * -2 = -10

z= −3 * -3 + 5 * 1 =14

Using the above values, we have:

The maximum value of the objective function is 26 and the minimum is -10

Read more about linear programming at:

brainly.com/question/15417573

#SPJ1

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First set up the equation to find answer: y=7-x. Then add it to the variable. 3x-1(7-x)=1. So that makes it 3x+-7+-1=1. Add like terms -7+-1=-8, so 3x+-8=1. Now to find x just switch the 8 to the other side. So you end up with 3x=9 since when you take away a number from one side you need to use the opposite value so adding 8 to -8 will cancel it out, then add it to the other, then just divide. 9/3=3, from here just substitute to find y. y=7+3. y=10. The answer is x=2 and y=5. I hope I helped!

5 0
3 years ago
Read 2 more answers
Sarah would like to make a 6 lb nut mixture that is 60% peanuts and 40% almonds. She has several pounds of a mixture that is 80%
ivolga24 [154]

Answer:  

<em>a.  The system of equations that models the situation is....</em>

<em>     0.80x+0.50y=3.60\\\\ 0.20x+0.50y=2.40</em>

<em>b.  The solution to the system:  x = 2 and y = 4 </em>

<em>The amount of 80/20 mixture is 2 pounds and the amount of 50/50              mixture is 4 pounds.</em>

Step-by-step explanation:

Suppose, the amount of 80/20 mixture is  x pounds and the amount of 50/50 mixture is  y pounds.

So, the amount of peanuts in 80/20 mixture = 0.80x pound and the amount of almonds in 80/20 mixture =0.20x pound.

And the amount of peanuts in 50/50 mixture =0.50y pound and the amount of almonds in 50/50 mixture =0.50y pound.

Now, Sarah would like to make a 6 pounds nut mixture that is 60% peanuts and 40% almonds.

So, the amount of peanuts in that mixture =(6\times 0.60)=3.60 pounds

and the amount of almonds in that mixture =(6 \times 0.40)= 2.40 pounds.

So, the system of equations will be.........

0.80x+0.50y=3.60 ...................(1)\\\\ 0.20x+0.50y=2.40...................(2)

Subtracting equation (2) from equation (1), we will get.....

(0.80x+0.50y)-(0.20x+0.50y)=3.60-2.40\\ \\ 0.60x=1.20\\ \\ x= \frac{1.20}{0.60}=2

Now, plugging this x=2 into equation (1), we will get......

0.80(2)+0.50y=3.60\\ \\ 1.60+0.50y=3.60\\ \\ 0.50y=3.60-1.60=2\\ \\ y=\frac{2}{0.50}=4

So, the amount of 80/20 mixture is 2 pounds and the amount of 50/50 mixture is 4 pounds.

7 0
3 years ago
What is msu?<br> 49°<br> 77°<br> 98°<br> 161°
givi [52]

Answer:

77°

Step-by-step explanation:

\\ T = \frac{1}{2}  (RU - SU)\\ \\ 21 =\frac{1}{2}(119 - SU)\\ \\ 42 = 119 - SU\\ SU=77

4 0
3 years ago
Read 2 more answers
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