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3 years ago

How do I construct bisectors, angles, & segments?

Mathematics

1 answer:

Doss [256]3 years ago

4 0

Answer:

Step-by-step explanation:

These come directly from my textbook, so I'm not sure if your teacher will accept this kind of work.

1. Angle construction:

Given an angle. construct an angle congruent to the given angle.

Given: Angle ABC

Construct: An angle congruent to angle ABC

Procedure:

1. Draw a ray. Label it ray RY.

2. Using B as center and any radius, draw an arc that intersects ray BA and ray BC. Label the points of intersection D and E, respectively.

3. Using R as center and the same radius as in Step 2, draw an arc intersecting ray RY. Label the arc XS, with S being the point where the arc intersects ray RY.

4. Using S as center and a radius equal to DE, draw an arc that intersects arc XS at a point Q.

5. Draw ray RQ.

Justification (for congruence): If you draw line segment DE and line segment QS, triangle DBE is congruent to triangle QRS (SSS postulate) Then angle QRS is congruent to angle ABC.

You can probably also Google videos if it's hard to imagine this. Sorry, construction is super hard to describe.

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Solve the following equation for n: <br><br>8 + n = 16.<br><br>

Nataly [62]

Answer:

n=8

Step-by-step explanation:

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3 years ago

Read 2 more answers

Find the area of the irregular shape. Round to the nearest tenth.

svp [43]

Given:
Irregular Shape:
Semi-circle and rectangle:

Area of a rectangle = l * w
Area of a semi-circle = (π r²)/2

Area of rectangle = 8 cm * 5 cm = 40cm²
Area of a semi-circle = (3.14 (4²))/2 = (3.14*16)/2 = 50.24/2 = 25.12cm²
4² is taken from diameter of 8cm divided by 2 to get the radius.

Total area = 40 cm² + 25.12 cm² = 65.12 cm²

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3 years ago

Which are the roots of the quadratic function f(b) = 62 – 75? Select two options.

elena55 [62]

Answer:

$b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}$

Step-by-step explanation:

Given

$f(b) = b^2 - 75$

Required

Determine the roots

To get the root of the function, then f(b) must be 0;

i.e. f(b) = 0

So, the expression becomes

$0 = b^2 - 75$

Add 75 to both sides

$75 + 0 = b^2 - 75 + 75$

$75 = b^2$

Take square roots of both sides

$\sqrt{75} = \sqrt{b^2}$

$\sqrt{75} = b$

Reorder

$b = \sqrt{75}$

Expand 75 as a product of 25 and 3

$b = \sqrt{25*3}$

Split the expression

$b = \sqrt{25} *\sqrt{3}$

$b = \±5 *\sqrt{3}$

$b = \±5 \sqrt{3}$

$b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}$

The options are not clear enough; however the roots of the equation are $b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}$

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3 years ago

When comparing answers on a group assignment, Jenny and Jeremy found that their answers did not match. Part 1: Who do you believ

vitfil [10]

PART 1:

Jeremy gives the correct answer.

The value of 0.41 [with a bar over the digit 4 and 1] shows that the digit 4 and 1 are reoccurring = 0.414141414141414141....

Jenny's assumption of 41/100 will give a decimal equivalency of 0.41 [without a bar over digit 4 and 1]. This value is not a reoccurring decimal value.

PART 2:

The long division method is shown in the picture below

PART 3:

As mentioned in PART 1, the result of converting 41/100 into a decimal is 0.41 [non-reoccuring decimal] while converting 41/99 into a decimal is 0.41414141... [re-occuring decimal]. The conjecture in PART 1 is correct

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3 years ago

Which expression is NOT equivalent to 2.89 × 0.6?

Rashid [163]

Answer:

(289x6)x(110x110)

Step-by-step explanation:

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3 years ago