Answer:
6.7% of employees at Solar Systems, Inc. are younger than 30 years old
Step-by-step explanation:
The mean of ages of the employees at Solar Systems is 32.7 years
Mean = 
Standard deviation =
We are supposed to find What percentage of employees at Solar Systems, Inc. are younger than 30 years old i.e.P(x<30)
So,

Z=-1.5
Refer the z table for p value
So,p value = 0.0668
So P(x<30)=0.0668= 6.68% = 6.7%
So, 6.7% of employees at Solar Systems, Inc. are younger than 30 years old
Y=13
(when you have fractions like the one in this problem, you get rid of them by multiplying both sides by the denominator.)
This in what I got:
(-7i)(10i)
-70i
Answer:
It a simultaneous equation so the solution is 2
Step-by-step explanation:
Answer:
-1 and 5
Step-by-step explanation: