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2 years ago

Solve the following equation:

Mathematics

1 answer:

saul85 [17]2 years ago

8 0

Answer:

to get ride of the x² you are gonna square root both sides so it is now 2x=5 divide by 2 on both sides and boom x=2.5

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Solve the inequalty 2 2/5 < b-8/15

mr_godi [17]

Answer:

b>44

Step-by-step explanation:

12/5<b-8/15

switch sides b-8/15>12/5

multiply both sides by 15 15(b-8)/15>12*15/5

simplify b-8>36

add 8 to both sides b-8+8>36+8

simplify

b>44

4 0

3 years ago

How to solve this problem <br><br>. 0.3 [1.57 – (0.6)²]

love history [14]

Well (1.57- 0.6 X 0.6) x 0.3 = 0.363

3 0

3 years ago

Read 2 more answers

If g (x) = 1/x then [g (x+h) - g (x)] /h

lys-0071 [83]

Answer:

$\dfrac{-1}{x(x+h)}, h\ne 0$

Step-by-step explanation:

If $g(x) = \dfrac{1}{x}$ , then $g(x+h) = \dfrac{1}{x+h}$ . It follows that

$\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}$

Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.

$\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\\&=\frac{1}{h} \left(\frac{x}{x(x+h)} - \frac{x+h}{x(x+h)} \right) \\ &=\frac{1}{h} \left(\frac{x-(x+h)}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{x-x-h}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{-h}{x(x+h)}\right) \end{aligned}$

Now we can cancel the h in the numerator and denominator under the assumption that h is not 0.

$= \dfrac{-1}{x(x+h)}, h\ne 0$

5 0

3 years ago

Ryan is performing an experiment. He starts with a solution that has a temperature of 12.2°C. He lowers the temperature 5 times

Anon25 [30]

Answer: The equation that can be used to find x, is given by

$-14.61^\circ C=12.2^\circ C-5x$

Step-by-step explanation:

Let the number of degrees he lowered the temperature by each time be 'x'.

Temperature he starts with = 12.2° C

Temperature he stopped with = -14.61° C

According to question, it is said that he lowers the temperature 5 times by the same amount each time.

So, it becomes,

$-14.61=12.2-5x\\\\-14.61-12.2=-5x\\\\-26.81=-5x\\\\\frac{26.81}{5}=x\\\\5.362^\circ C=x$

Hence, the equation that can be used to find x, is given by

$-14.61^\circ C=12.2^\circ C-5x$

8 0

3 years ago

Suppose you'd like to save enough money to pay cash for your next car. The goal is to save an extra $28,000 over the next 6 year

Anna35 [415]

Given:

• Amount to save, A = $28,000

• Time, t = 6 years

• Interest rate, r = 5.3% ==> 0.053

• Number of times compounded = quarterly = 4 times

Let's find the amount that must be deposited into the account quarterly.

Apply the formula:

$FV=P(\frac{(1+\frac{r}{n})^{nt}-1}{\frac{r}{n}})$

Where:

FV is the future value = $28,000

r = 0.053

n = 4

t = 6 years

Thus, we have:

$28000=P(\frac{(1+\frac{0.053}{4})^{4\times6}-1)}{\frac{0.053}{4}}$

Let's solve for P.

We have:

$\begin{gathered} 28000=P(\frac{(1+0.01325)^{24}-1}{0.01325}) \\ \\ 28000=P(\frac{(1.01325)^{24}-1)^{}}{0.01325}) \\ \\ 28000=P(\frac{1.371509114-1}{0.01325}) \\ \\ 28000=P(\frac{0.371509114}{0.01325}) \end{gathered}$

Solving further:

$28000=P(28.0384237)$

Divide both sides by 28.0384237:

$\begin{gathered} \frac{28000}{28.0384237}=\frac{P(28.0384237)}{28.0384237} \\ \\ 998.6=P \\ \\ P=998.6 \end{gathered}$

Therefore, the amount that must be deposited quarterly into the account is $998.60

ANSWER:

$998.60

8 0

1 year ago