The architect earns $47000 yearly and the lawyer earns $68,000 yearly.
<h3>How to solve algebra problems?</h3>
Let x = salary of architect, in thousands
Let 2x - 26 be the salary of lawyer, in thousands
Thus, if their salary combined is $214 thousand, then we have the algebra expression;
2x + 2x - 26 = 214
4x - 26 = 214
4x = 214 - 26
4x = 188
x = 47, in thousands.
The architect earns $47000 yearly
The lawyer earns 2(47000) - 26000 = $68,000 yearly
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We can solve using y = 0 and solving for x.
81x + 18(0) = 9
81x = 9
x = 1/9
Therefore, the point (1/9, 0) sastisfies the equation.
Best of Luck!
3 ( 2t + 5 ) = 5 t + 25
3 * 2 t + 3 * 5 = 5 t + 25
6 t + 15 = 5 t + 25
6t - 5t = 25 - 15
t = 10
Hope this helps!
Your answer is 77!
All you really need to do is 231/3 since you need to find out how many students are in the freshman class.
