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1 year ago

Please help. Attached as an image

Mathematics

1 answer:

Triss [41]1 year ago

4 0

Distance formula ds = v(dx² + dy²) s = ? v(1 + (dy/dx)²) dx ......... s = the arc length y = 171 - x²/45

chegg

someone solved it on this

https://youtu.be/UGjXlMVdZvc

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Using the equation y=kx and the table below, find the constant of proportionality (k).

elena-s [515]

Answer:

k = 9/4

Step-by-step explanation:

To find k, use the equation

y = kx

Pick a point

72 = k *32

Divide each side by 32

72/32 = k

9/4 = k

4 0

2 years ago

Read 2 more answers

Find the missing numbers.

irinina [24]

Answers

1. 6
2. 1
3. 4

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3 years ago

Read 2 more answers

Does the graph represent a function?

AlekseyPX

Answer:

no it does not you can identify that by doing the vertical line test

Step-by-step explanation:

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3 years ago

Y=x +3<br>1 23x+2y=-4<br>what is it

erik [133]

Answer:

x=-0.08 and y=2.92

Step-by-step explanation:

123x + 2(x+3) = -4 y = -0.08 + 3

123x + 2x + 6 = -4 = 2.92

125x + 6 = -4

125x = -10

x= -0.08

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2 years ago

Trucks in a delivery fleet travel a mean of 110 miles per day with a standard deviation of 38 miles per day. The mileage per day

Montano1993 [528]

Answer: 0.1824

Step-by-step explanation:

Given : The mileage per day is distributed normally with

Mean : $\mu=110\text{ miles per day}$

Standard deviation : $\sigma=38\text{ miles per day}$

Let X be the random variable that represents the distance traveled by truck in one day .

Now, calculate the z-score :-

$z=\dfrac{x-\mu}{\sigma}$

For x= 132 miles per day.

$z=\dfrac{132-110}{38}\approx0.58$

For x= 159 miles per day.

$z=\dfrac{159-110}{38}\approx1.29$

Now by using standard normal distribution table, the probability that a truck drives between 132 and 159 miles in a day will be :-

$P(132$

Hence, the probability that a truck drives between 132 and 159 miles in a day =0.1824

6 0

3 years ago