A rate that describes how much smaller or larger the scale drawing is than then real object

1 answer:

6 0

I'm not sure what is being asked here, but a rate that describes how much smaller or larger the scale drawing is than the real object would be a ratio such as 1in:25ft

You might be interested in

According to the U.S. Census Bureau, 42% of men who worked at home were college graduates. In a sample of 480 women who worked a

Likurg_2 [28]

Answer:

1) $0.327 - 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.315$

The point estimate for the proportion of college graduates among women who work at home is 0.327

2) $0.327 - 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.315$

$0.327 + 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.339$

The 80% confidence interval is given by (0.315; 0.339)

Step-by-step explanation:

For this case we have the following info given:

$X = 157$ represent the women who worked at home who were college graduates

$n = 480$ the sample size selected

Part 1

In order to find the proportion of college graduates among women who work at home and we can use the following formula:

$\hat p=\frac{X}{n} = \frac{157}{480}= 0.327$

The point estimate for the proportion of college graduates among women who work at home is 0.327

Part 2

Construct an 80% confidence interval for the proportion of women who work at home who are college graduates. Round the answer to three decimal places. An 80% confidence interval for the proportion of women who work at home Is < p <

The confidence interval for the true proportion would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 80% confidence interval the value for the significance is $\alpha=1-0.8=0.2$ and $\alpha/2=0.1$ , the critical value would be given by:

$z_{\alpha/2}=0.539$

And replacing we goot:

$0.327 - 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.315$

$0.327 + 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.339$

The 80% confidence interval is given by (0.315; 0.339)

6 0

3 years ago

Describe how the cosecant, secant and cotangent are related to the first three trigonometric functions learned.

saw5 [17]

$\bf \underline{sin(\theta)}=\cfrac{1}{csc(\theta)}
\qquad 
% cosine
\underline{cos(\theta)}=\cfrac{1}{sec(\theta)}
\qquad 
% tangent
tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}
\\\\\\
% cotangent
csc(\theta)=\cfrac{1}{\underline{sin(\theta)}}
\qquad 
% secant
sec(\theta)=\cfrac{1}{\underline{cos(\theta)}}\qquad 
\begin{array}{llll}
cot(\theta)
\begin{cases}
\cfrac{cos(\theta)}{sin(\theta)}\\\\
\cfrac{1}{tan(\theta )}
\end{cases}
\end{array}$