Answer:
The value of the snack bar is $ 2 and that of the magazine subscription is 25 $
Step-by-step explanation:
We have a system of two equations and two unknowns, which would be the following:
let "x" be the cost of the snack bar
Let "y" be the cost of the magazine subscription
16 * x + 4 * y = 132
20 * x + 6 * y = 190 => y = (190 - 20 * x) / 6
replacing:
16 * x + 4 * (190 - 20 * x) / 6 = 132
16 * x + 126.66 - 13.33 * x = 132
2.66 * x = 132 - 126.66
x = 5.34 / 2.66
x = 2
for "y":
y = (190 - 20 * 2) / 6
y = 25
Which means that the value of the snack bar is $ 2 and that of the magazine subscription is 25 $
Hi there!
Okay, so I was a bit confused by your question, but I tried to make it a bit easier and work out.
There was two ways I did this because I didn't want to NOT answer your question!
What about this:
3.2/15 cannot be simplified lower than what it is. Decimal form is 0.2133333 (repeating). I answered this part because I didn't know what 3. was (I at first thought it was part of the numerator. But now that I look at it again it may have been a question number. But just in case, I answered it like this anyway.)
Next!
I solved 2/15, which also cannot be simplified down lower than what it is. It's decimal form is 0.133333 (another repeating decimal.)
And so as you can see I answered two problems for you. If these are incorrect, let me know!
Hope this helps!
The answer to the equation is X= 27
Answer:
EF , HG , Parallel
Step-by-step explanation:
Here we are given a translated quadrilateral EFGH from Quadrilateral ABCD.
Also given that AB was parallel to DC.
Now we have to fill in the certain blanks.
Here EF is parallel to AB , As EFGH is a translated image of ABCD. And EF and AB are the corresponding sides.
Also HG is parallel to DC, EFGH is a translated image of ABCD.
Also we are given that AB is parallel to DC. Hence we have following results.
AB║DC
AB║EF
Hence CD║EF
also
CD ║HG
CD║EF
Hence we can come to conclusion that
EF║HG
Hence our answer will be
corresponding segments EF and HG are parallel to each other.
