A circle has a radius of 7cm . find the radian measure of the central angle ? that intercepts an arc of length 16cm .

PLEASE HELP ILL MARK BRAILIEST! A rectangle has an area of 4 square meters. The width is 1/5 meter. What is the length of the re

Lesechka [4]

20

Step-by-step explanation:

1/5 x 20 = 4

6 0

3 years ago

B = 10 feet area = 35 feet 2 Find the height of the triangle.

Alexandra [31]

Answer:

Height is 7m

Step-by-step explanation:

B = 10 feet area = 35 feet 2 Find the height of the triangle.

Area of triangle = 1/2 b×h

35 = 1/2(10×h)

35 × 2 = 10h

70 = 10h

h = 70/10

h = 7m

8 0

4 years ago

Solve. Round to the nearest tenth. 6 2-12 19 2x-2 HELP ASAP!!

Strike441 [17]

Answer:

$\displaystyle x = \frac{216}{7}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Step-by-step explanation:

Step 1: Define

$\displaystyle \frac{6}{19} = \frac{x - 12}{2x - 2}$

Step 2: Solve for x

Cross-multiply: $\displaystyle 6(2x - 2) = 19(x - 12)$
Distribute: $\displaystyle 12x - 12 = 19x - 228$
Isolate x terms: $\displaystyle -12 = 7x - 228$
Isolate x term: $\displaystyle 216 = 7x$
Isolate x: $\displaystyle \frac{216}{7} = x$
Rewrite: $\displaystyle x = \frac{216}{7}$

6 0

3 years ago

Read 2 more answers

Find the perimeter of a rectangle with a width of (x - 3) and a length of 4x

Firdavs [7]

Step-by-step explanation:

4x

__________

| |

x-3| | x-3

| |

|__________

4x

Add all sides together to get perimeter

2(4x)+2(x-3)=10x-6

7 0

3 years ago

When an electric current passes through two resistors with resistance r1 and r2, connected in parallel, the combined resistance,

kondaur [170]

Answer:

a)

The combined resistance of a circuit consisting of two resistors in parallel is given by:

$\frac{1}{R}=\frac{1}{r_1}+\frac{1}{r_2}$

where

R is the combined resistance

$r_1, r_2$ are the two resistors

We can re-write the expression as follows:

$\frac{1}{R}=\frac{r_1+r_2}{r_1r_2}$

Or

$R=\frac{r_1 r_2}{r_1+r_2}$

In order to see if the function is increasing in r1, we calculate the derivative with respect to r1: if the derivative if > 0, then the function is increasing.

The derivative of R with respect to r1 is:

$\frac{dR}{dr_1}=\frac{r_2(r_1+r_2)-1(r_1r_2)}{(r_1+r_2)^2}=\frac{r_2^2}{(r_1+r_2)^2}$

We notice that the derivative is a fraction of two squared terms: therefore, both factors are positive, so the derivative is always positive, and this means that R is an increasing function of r1.

b)

To solve this part, we use again the expression for R written in part a:

$R=\frac{r_1 r_2}{r_1+r_2}$

We start by noticing that there is a limit on the allowed values for r1: in fact, r1 must be strictly positive,

$r_1>0$

So the interval of allowed values for r1 is

$0$

From part a), we also said that the function is increasing versus r1 over the whole domain. This means that if we consider a certain interval

a ≤ r1 ≤ b

The maximum of the function (R) will occur at the maximum value of r1 in this interval: so, at

$r_1=b$

6 0

3 years ago