Question

Alice and Bob both go to a party which starts at $5:00$. Each of them arrives at a random time between $5:00$ and $6:00$. What is the probability that the number of minutes Alice is late for the party plus the number of minutes Bob is late for the party is less than $45$

Answer 1

The probability comes out to be 9/32.

Deducing Arrival Time Possibility

All the possible arrival times by Alice and Bob, in minutes after 5 PM, is constrained by the values of given values of x and y,

x = 0, y = 0, x = 60, y = 60.

Here, let the values of x represent how many minutes after 5 PM Alice arrives at the party.

Let the y values represent the time in minutes that Bob arrives at the party after 5 PM.

Calculating the Required Probability

The times that concern us, however, are obtained by the following probability function,

x + y ≤ 45.

And x = 0, y = 0, and x + y ≤ 45 define the constraints of this probability function. Thus the perimeter of such a graph will be given as,

(45² / 2) = 1012.5 square units

Since the total area of the various arrival times is 60 x 60, or 3600 square units, the probability that Alice and Bob will arrive together after 5 o'clock in the evening in less than 45 minutes is therefore = 1012.5 / 3600 = 9/32

Learn more about probability here:

brainly.com/question/11234923

#SPJ4