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Paladinen [302]
2 years ago
9

Alice and Bob both go to a party which starts at $5:00$. Each of them arrives at a random time between $5:00$ and $6:00$. What i

s the probability that the number of minutes Alice is late for the party plus the number of minutes Bob is late for the party is less than $45$
Mathematics
1 answer:
faltersainse [42]2 years ago
3 0

The probability comes out to be 9/32.

Deducing Arrival Time Possibility

All the possible arrival times by Alice and Bob, in minutes after 5 PM, is constrained by the values of given values of x and y,

x = 0, y = 0, x = 60, y = 60.

Here, let the values of x represent how many minutes after 5 PM Alice arrives at the party.

Let the y values represent the time in minutes that Bob arrives at the party after 5 PM.

Calculating the Required Probability

The times that concern us, however, are obtained by the following probability function,

x + y ≤ 45.

And x = 0, y = 0, and x + y ≤ 45 define the constraints of this probability function. Thus the perimeter of such a graph will be given as,

(45² / 2) = 1012.5 square units

Since the total area of the various arrival times is 60 x 60, or 3600 square units, the probability that Alice and Bob will arrive together after 5 o'clock in the evening in less than 45 minutes is therefore = 1012.5 / 3600 = 9/32

Learn more about probability here:

brainly.com/question/11234923

#SPJ4

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LekaFEV [45]

Answer:

Four squared equals 16

Step-by-step explanation:

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2 years ago
What dimensions of the box are required to fit the candle? 5 by 6 by 18 7 by 6 by 18 5 by 3 by 18 7 by 3 by 18
LiRa [457]
The minimum height of the box must be 18 units, which is present in all the choices.
Another minimum dimension that we already know is 7 units, since it is an oblique box, and the projection of bottom-left to top-right is shown as 7 units.
That leaves us with the second (7x6) or fourth choice (7x3).

We have not been given the other dimension of the triangle, but from common sense, it looks longer than the front (5 units) leg, therefore 6 units is not an unreasonable dimension.

With 99.5% certainty, I would choose the second choice (7x6x18) because the remaining dimension does not look like 3 units long.
4 0
3 years ago
a crew of highway workers paved 2/15 mile in 20 minutes.if they continued working at the same rate,what portion of a mile wil th
icang [17]

Answer:

2/5 of a mile

Step-by-step explanation:

The easiest approach is to realise that one hour is 3 times longer than  

20 minutes. The longer the time, the more they will pave.


2/5  of a mile, in 20 minutes, how much in 60 minutes?(#)

They will pave 3 times more.

2/15 x 3/1 = 6/15 of a mile

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8 0
3 years ago
Please help me with this
Llana [10]
4 unknowns needs 4 equations. I'll call the unknown numbers a,b,c,d in that order left to right.

4 + a = b
a + b = c
b + c = d
c + d = 67

let's use substitution to get rid to combine equations and get rid of variables.
If a + b = c then a = c - b
4 + (c - b) = b
4 + c = 2b

If b + c = d then b = d - c
4 + c = 2(d - c)
4 + c = 2d - 2c
4 + 3c = 2d

then we have c + d = 67 so c = 67 - d

4 + 3(67 - d) = 2d
4 + 201 - 3d = 2d
205 = 5d
d = 41

Should be easy now, subtract backwards.

67 - 41 = 26
41 - 26 = 15
26 - 15 = 11
15 - 11 = 4

4, 11, 15, 26, 41, 67


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3 years ago
Which of the following demonstrates the commutative property across multiplication for 2× 10 × 7
Phoenix [80]
Its A. Kelp dont you dare.

5 0
3 years ago
Read 2 more answers
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