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Paladinen [302]
2 years ago
9

Alice and Bob both go to a party which starts at $5:00$. Each of them arrives at a random time between $5:00$ and $6:00$. What i

s the probability that the number of minutes Alice is late for the party plus the number of minutes Bob is late for the party is less than $45$
Mathematics
1 answer:
faltersainse [42]2 years ago
3 0

The probability comes out to be 9/32.

Deducing Arrival Time Possibility

All the possible arrival times by Alice and Bob, in minutes after 5 PM, is constrained by the values of given values of x and y,

x = 0, y = 0, x = 60, y = 60.

Here, let the values of x represent how many minutes after 5 PM Alice arrives at the party.

Let the y values represent the time in minutes that Bob arrives at the party after 5 PM.

Calculating the Required Probability

The times that concern us, however, are obtained by the following probability function,

x + y ≤ 45.

And x = 0, y = 0, and x + y ≤ 45 define the constraints of this probability function. Thus the perimeter of such a graph will be given as,

(45² / 2) = 1012.5 square units

Since the total area of the various arrival times is 60 x 60, or 3600 square units, the probability that Alice and Bob will arrive together after 5 o'clock in the evening in less than 45 minutes is therefore = 1012.5 / 3600 = 9/32

Learn more about probability here:

brainly.com/question/11234923

#SPJ4

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Answer:

x^6 + 2 x^5 - 6 x^4 + 3 x^2 + 6 x - 18

Step-by-step explanation:

f(x) = x^2 +2x-6

g(x) =x^4+3

We want to find f*g

(f*g)(x) = (x^2 +2x-6)(x^4+3)

Distribute

          =x^2*x^4 +3x^2 +2x*x^4 +2x*3 +-6x^4 -6*3

         = x^6 +3x^ +2x^5 +2x^3 -6x^4 -18

Combine like terms

         =x^6 + 2 x^5 - 6 x^4 + 3 x^2 + 6 x - 18

8 0
3 years ago
Brainiest to whoever right !
Blababa [14]

Answer:

m<RST = 32°

m<TSQ = 58°

Step-by-step explanation:

m<RST here, meaning the angle of the whole diagram is 90 degrees as you can see.

m<RSQ + m<TSQ = m<RST

15x — 43 + 8x + 18 = 90

23x — 25 = 90

       +25     +25

---------------------------

23x = 115

/23      /23

----------------------------

x = 5

Now, plug this into the equation for m<RSQ and m<TSQ to find their values.

m<RSQ = 15x — 43

= 15x - 43

= 15(5) - 43

= 75 - 43

= 32

m<TSQ = 8x + 18

= 8x + 18

= 8(5) + 18

= 40 + 18

= 58

Now, check to see if our values are right or not.

15x — 43 + 8x + 18 = 90

15(5) — 43 + 8(5) + 18 = 90

75 - 43 + 40 + 18 = 90

32 + 40 + 18 = 90

90 = 90 <u>CORRECT</u>

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3 years ago
The chef at a restaurant bought 37 pounds of salad for $46.25. How much did she pay for 1 pound of salad? Show all work and expl
Art [367]

Answer:

$1,25

Step-by-step explanation:

$46.25 : 37 = $1,25

I divided the amount of money into the number of 37 pounds

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Over [174]
100cm = 1m so 2m 50cm = 250cm + 56cm= 306cm which means the answer is 3m 6 cm
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3 years ago
At the park, there is a triangular sandbox with base = 12ft and height = 4ft. A drawing of the sandbox is shown above. Brie want
sammy [17]

Your question is not clear, but it looks as though you want to know how Brie can make a similar sandbox with base = 8ft.

Answer:

For Brie to make a similar sandbox, he must use a base = 8ft, and height = (8/3)ft

Step-by-step explanation:

It is possible for Brie to make a similar triangular sandbox with base = 12ft and height = 4ft.

All he must ensure is that the ratio of base to height of the original sandbox is the same ratio of base to height of the one he is trying to make.

The original sandbox is 12:4

Because he wants to use a base = 8ft, the sandbox he is trying to make is 8:x

Where x is the height of the sandbox he is trying to make.

Then for these sandboxes to be similar, the ratio 12:4 = 8:x

=> 12/4 = 8/x

12x = 8 × 4

12x = 32

x = 8/3

The height must be (8/3)ft

3 0
3 years ago
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