If we denote a cystic fibrosis gene with a c and a disease-free gene with a C (since the disease is recessive), then only a c

Question

3 years ago

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If we denote a cystic fibrosis gene with a c and a disease-free gene with a C (since the disease is recessive), then only a c

c person will actually have the disease. Such persons would ordinarily die before parenting children, but a child can also inherit the disease from two Cc parents (who themselves are healthy—that is, have no symptoms but are "carriers" of the disease). Suppose a child is born to one cystic fibrosis carrier parent and one non-carrier parent. Find the probability that that the child will be a carrier.

Mathematics

1 answer:

Ksju [112] · Answer 1 · 2022-02-09T03:31:57+03:00

Ksju [112]3 years ago

8 0

With a simple punnett square we see that there is a 50% chance the child will be a carrier.

If we denote a cystic fibrosis gene with a c and a​ disease-free gene with a C​ (since the disease is​ recessive), then only a c

If we denote a cystic fibrosis gene with a c and a disease-free gene with a C (since the disease is recessive), then only a c