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Makovka662 [10]
1 year ago
9

Can u guys pls help me with this homework

Mathematics
1 answer:
gladu [14]1 year ago
6 0

The value of √(7 * 23 - 1)/8 is 4.47, the values of a, b and c are -14/11, -10/11 and 3, respectively and the area of the shape is 5√5 + 5 square meters

<h3>How to evaluate the radical expression?</h3>

The question goes thus:

If √5 = 2.236, evaluate √(7 * 23 - 1)/8

We have:

√(7 * 23 - 1)/8

Evaluate the product of 7 and 23

√(7 * 23 - 1)/8 = √(161 - 1)/8

Evaluate the difference of 161 and 1

√(7 * 23 - 1)/8 = √160/8

Evaluate the quotient of 160 and 8

√(7 * 23 - 1)/8 = √20

Express 20 as the product 4 and 5

√(7 * 23 - 1)/8 = √(4 * 5)

Expand the product

√(7 * 23 - 1)/8 = √4 * √5

Express √4 as 2

√(7 * 23 - 1)/8 = 2 * √5

Substitute √5 = 2.236

√(7 * 23 - 1)/8 = 2 * 2.236

Evaluate the product

√(7 * 23 - 1)/8 = 4.472

Approximate

√(7 * 23 - 1)/8 = 4.47

Hence, the value of √(7 * 23 - 1)/8 is 4.47

<h3>How to simplify the radical expression?</h3>

The expression is given as:

(3√2 + 5√6)/(3√2 - 5√6)

Rationalize the above expression

(3√2 + 5√6)/(3√2 - 5√6) * (3√2 + 5√6)/(3√2 + 5√6)

Evaluate the product

(3√2 + 5√6)²/((3√2)² - (5√6)²)

Simplify the denominator

(3√2 + 5√6)²/(18 - 150)

This gives

[(3√2)² + (5√6)² + 2 *(3√2) * (5√6)]/(-132)

Simplify the numerator

[168 + 120√3]/(-132)

Simplify the fraction

-14/11 - 10√3/11

Hence, the values of a, b and c are -14/11, -10/11 and 3, respectively

<h3>How to determine the area?</h3>

The area is calculated as:

A = 1/2 * (Sum of parallel bases) * Height

So, we have:

A = 1/2 * (4 + 3√5 + 6 - √5) * √5

Evaluate the like terms

A = 1/2 * (10 + 2√5) * √5

Evaluate the product

A = (5 + √5) * √5

Evaluate the product

A = 5√5 + 5

Hence, the area of the shape is 5√5 + 5 square meters

Read more about rational expressions at:

brainly.com/question/8008240

#SPJ1

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\textsf{Hey there!}

\mathsf{\dfrac{3}{5}n +15=10+\dfrac{2}{5}n}

\mathsf{\bf{SUBTRACT}\ \mathsf{by\ \dfrac{2}{5}n\ from\ both\ of\ your\ sides}}

\mathsf{Like: \dfrac{3}{5}n+15-\dfrac{2}{5}n=\dfrac{2}{5}n+10-\dfrac{2}{5}n}

\mathsf{\bf{CANCEL: \dfrac{3}{5}+\dfrac{2}{5}}}\textsf{out\ because that gives you\ 1}

\textsf{Solve\ the set we have left over}

\mathsf{Our\ new\ equation\ becomes: \dfrac{1}{5}n+15=10}

\mathsf{\bf{SUBTRACT}}\textsf{ by 15 on both of your sides}

\mathsf{\dfrac{1}{5}n+15-15=10-15}

\mathsf{Cancel\ out: 15-15\ because\ that\gives\ you\ 0 }

\mathsf{Keep: 10-15\ because\ it\ helps\ us\ solve\ for\ your\ n }

\mathsf{10-15=-5}

\mathsf{New\ equation: \dfrac{1}{5}n=-5}

\mathsf{\bf{MULTIPLY}\mathsf{\ both\ sides\ by\ 5}}

\mathsf{\dfrac{1}{5}n\times5=5\times-5}

\mathsf{Cancel\ out\ \dfrac{1}{5}\times5 \ because \  it \ gives \ us \ 1}\mathsf{Keep: 5\times -5\ because\ it\gives\ us\ the\ value\ of\ your\ n}

\mathsf{n =5\times-5}\\\mathsf{5\times-5 = -25}

\textsf{Thus, \underline{\bf{n = -25}}}\checkmark

\boxed{\boxed{\mathsf{Thus,\ your\ answer\ is: \boxed{\boxed{\bf{n =-25}}}}}}\checkmark

\textsf{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

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