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nalin [4]
2 years ago
8

Given right triangle JKL, what is the value of cos(L)?

Mathematics
1 answer:
brilliants [131]2 years ago
5 0

The value of cos(L) in the triangle is Five-thirteenths

<h3>What are right triangles?</h3>

Right triangles are triangles whose one of its angle has a measure of 90 degrees

<h3>How to determine the value of cos(L)?</h3>

The value of a cosine function is calculated as:

cos(L) = Adjacent/Hypotenuse

The hypotenuse is calculated as

Hypotenuse^2 = Opposite^2 + Adjacent^2

So, we have:

Hypotenuse^2 = 12^2 + 5^2

Evaluate

Hypotenuse^2 = 169

Take the square root of both sides

Hypotenuse = 13

So, we have

Adjacent = 5

Hypotenuse = 13

Recall that

cos(L) = Adjacent/Hypotenuse

This gives

cos(L) = 5/13

Hence, the value of cos(L) in the triangle is Five-thirteenths

Read more about right triangles at:

brainly.com/question/2437195

#SPJ1

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