Find the vertex of the function given below y=x^2-2x+1
1 answer:
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Answer:
(1, 0).
Step-by-step explanation:
Convert from standard form to vertex form by completing the square:
y = x² - 2x + 1
Move 1 to the other side:
-1 = x² - 2x
Complete the square. Remember to add to both sides:
-1 + (1) = x² -2x + 1
Simplify:
0 = (x - 1)²
The function in vertex form is:
y = (x - 1)²
Therefore, the vertex is:
(1, 0).
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