Ask question

Ask question

All categories

3 years ago

14

Mila’s dog weighs 4 pounds more than eight times the way of keikos dog which expression could be used to find the way of Milan’s

dog

1 answer:

Hunter-Best [27]3 years ago

6 0

X= weight of Keiko's dog
m= weight of Milan's dog

Weight of Milan's dog's equals (8 times the weight of Keiko's dog) plus 4 pounds.

Expression: m= 8x + 4

Hope this helps! :)

You might be interested in

Estimate the original volume of the pyramid in Fig. 15.28, given that its frustum has a 4 m by 4 m square top which is 12 m vert

puteri [66]

The volume of the pyramid is 2496 cu.m.

<h3>What is a Pyramid ?</h3>

A pyramid is a three dimensional structure which has a polygon base and in general triangular faces which join at the top .

It is given that

A pyramid $\rm frustum$ has a 4 m by 4 m square top

Height = 12 m

Base = 20 m

The volume of a square pyramid with a $\rm frustum$ is given by

V = (1/2) * ( Area of base + Area of $\rm frustum$ ) * height of the $\rm frustum$ from the base

V = 0.5 * ( 20 *20 + 4*4 ) * 12

V = 2496 cu.m

The volume of the pyramid is 2496 cu.m.

To know more about Pyramid

brainly.com/question/13057463

#SPJ1

8 0

2 years ago

This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex

pashok25 [27]

Answer with Step-by-step explanation:

We are given that

$f(x,y,z)=10x+10y+3z$

$g(x,y,z)=5x^2+5y^2+3z^2=43$

We have to find the extreme values of the function.

$f_x(x,y,z)=10,f_y(x,y,z)=10,f_z(x,y,z)=3$

$g_x(x,y,z)=10x,g_y(x,y,z)=10y,g_z(x,y,z)=6z$

$\Delta f(x,y,z)=\lambda \Delta g(x,y,z)$

Therefore,

$10=\lambda 10x\implies x=\frac{1}{\lambda}$

$10=10y\lambda\implies y=\frac{1}{\lambda}$

$3=6z\lambda$

$z=\frac{1}{2\lambda}$

Substitute the values in g(x)

Then, we get

$\frac{5}{\lambda^2}+\frac{5}{\lambda^2}+\frac{3}{4\lambda^2}=43$

$\frac{20+20+3}{4\lambda^2}=43$

$\frac{43}{4\lambda^2}=43$

$\lambda^2=\frac{43}{4\times 43}$

$\lambda=\pm\frac{1}{2}$

When $\lambda=\frac{1}{2}$ then,

$x=2,y=2,z=1$

When $\lambda=-\frac{1}{2}$

Then, $x=-2,y=-2,z=-1$

$f(2,2,1)=10+10+3=23$

$f(-2,-2,-1)=-10-10-3=-23$

Hence, maximum value of f(x,y,z) is 23 at (2,2,1) and minimum value of f(x,y,z) is -23 at (-2,-2 ,-1).

8 0

4 years ago

Pls help, need the answer quick!

Assoli18 [71]

Ty can cut 3.3333 because 15+15=30 30/9=3.333

6 0

3 years ago

Howard cuts 54 centimeters off 1-meter boards. How much of the board does Howard have left.

oee [108]

100 cm in a meter. 100-54=46.
46 cm left

6 0

3 years ago

What is the value of x to the nearest tenth

serg [7]

Answer:

8.0

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers