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Serhud [2]
2 years ago
6

E and F are two events and that P(E)=0.2 and P(F/E)=0.6 what is P(E and F)

Mathematics
1 answer:
AVprozaik [17]2 years ago
5 0

The probability of E and F expressed as P(E and F) equals;0.12

<h3>How to solve Conditional Probability?</h3>

We are given;

P(E) = 0.2

P(F|E) = 0.6

Now, P(F/E) is known as conditional probability and it means the probability of event F given the probability of another event E. This can be expressed as; P(F|E) = P(E and F)/P(E)

Thus;

P(E and F) = 0.2 * 0.6

P(E and F) = 0.12

Read more about Conditional Probability at; brainly.com/question/23382435

#SPJ1

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A rocket is fired directly upwards with a velocity of 80 ft/sec. The equation for its height, H, as a function of time, t, is
sleet_krkn [62]

Answer:

(c).

Step-by-step explanation:

h(t) = - 16 t² + 80 t

Coordinates of the vertex are:

<em>t</em> = - \frac{80}{2(-16)} = \frac{5}{2} = <em>2.5 sec. </em>

<em>h</em> = - 16(2.5)² + 80(2.5) = - 100 + 200 = <em>100 ft</em>.

3 0
3 years ago
The scale factor from M to L is 3/2. What is the scale factor from L to M?
spin [16.1K]

Answer:

2/3

Step-by-step explanation:

its right

6 0
3 years ago
If 49=83m, What is the value of m?
maw [93]

Answer:

49/83 = m

Step-by-step explanation:

49=83m

Divide each side by 83

49/83 = 83m/83

49/83 = m

6 0
4 years ago
What is the solution to<br><br> −(6m+8) =4(17−m)
Sedbober [7]

Answer:

\boxed{m = -38}

Step-by-step explanation:

-(6m+8) =4(17-m)

→ Expand brackets

-6m-8=68-4m

→ Add 8 to both sides to collect the whole numbers

-6m = 76-4m

→ Add -4m to both sides to collect the m terms

-2m=76

→ Divide both sides by -10 to isolate m

m=-38

8 0
3 years ago
How to work it out logically? Question a !!!
Arturiano [62]

Answer:

Fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.

Step-by-step explanation:

Given the figure with dimensions. we have to find the area of given figure.

Area of figure=ar(1)+ar(2)+ar(3)

Area of region 1 = ar(ANGI)+ar(AIB)

                          =L\times B+\frac{1}{2}\times base\times height\\\\=[1500\times (5000-2000-1500)]+\frac{1}{2}\times (3000-1500)\times (5000-2000-1500)\\\\=3375000m^2=337.5ha

Area of region 2 = ar(DHBC)

                       =2000\times1500\\\\=3000000m^2=300ha

Area of region 3 = ar(GFEH)

                             (2000+1500)\times 1000\\\\=3500000m^2=350ha

Hence, Area of figure=ar(1)+ar(2)+ar(3)=337.5ha+300ha+350ha

                                                 =987.5 ha

Now, we have to do straight-line fencing such that area become half and cost of fencing is minimum.

Let the fencing be done through x m downward from B which divides the two into equal area.

⇒ Area of upper part above fencing=Area of lower part below fencing

⇒ar(ANGB)+ar(GKLB)=ar(KLCM)+ar(MDCF)\\\\337500+3000x=(3500-x)\times 1000+2000(1500-x)\\\\3375000+3000x=3500000-1000x+3000000-2000x\\\\6000x=315000\\\\x=\frac{315000}{6000}=520.8m

Hence, fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.

7 0
3 years ago
Read 2 more answers
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