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NeTakaya
2 years ago
7

Find the equation of a circle centered on the origin going through the point (-5,3)

Mathematics
1 answer:
11111nata11111 [884]2 years ago
6 0

The given center and point on the circle of (0,0) and (-5, 3), respectively

gives the equation of the circle as x^{2} +y^{2} =\sqrt{34}.

The general form of the equation of the circle is presented as follows

(x - h)² + (y - k)² = r²

Where,(h, k) is the center of the circle and r is the radius of the circle

Here (h, k) is centered about the origin and the radius of the circle

Radius of the circle = √[(-5-0)² + (3-0)²]

= √(25+9)

=√34.

The equation of a circle centered on the origin going through the point (-5,3)

x^{2} +y^{2} =\sqrt{34}

Learn more about the equation of a circle brainly.com/question/502872

#SPJ4

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The width of a rectangle measures (8.4x + 2.2) centimeters, and its length
lorasvet [3.4K]

The algebraic expression that will represent the perimeter in centimeters of the given rectangle is:  (25.8x +11.2) $ cm

<em><u>Recall:</u></em>

Perimeter of a rectangle = 2(L + W)

<em>Given the following dimension of a </em><em>rectangle</em><em>:</em>

  • width (W) = (8.4x + 2.2) cm
  • length (L) = (4.5x + 3.4) cm

To find the expression that represents the perimeter, plug in the given values into the formula for perimeter.

  • Thus:

Perimeter = 2((4.5x + 3.4) + (8.4x + 2.2))

  • Open the bracket

Perimeter = 2(4.5x + 3.4 + 8.4x + 2.2)

  • Add like terms together

Perimeter = 2(12.9x + 5.6)

  • Multiply

Perimeter = 25.8x +11.2

Therefore, the algebraic expression that will represent the perimeter in centimeters of the given rectangle is:  (25.8x +11.2) $ cm

Learn more here:

brainly.com/question/18869010

3 0
3 years ago
Help please I’m not sure how to do this
joja [24]

the answer for this would be the last one. two rays that meet at a end point.

hope this helps!

3 0
4 years ago
Read 2 more answers
HURRY ASAP,100 POINTS ARE ON THE LINE!
Allushta [10]

Answer:

<h3>From my analysis:</h3><h3>2 ⁷/9 = 25/9 (improper fraction)</h3><h3>25 ÷ 9 = 2.777777777777777</h3>

<h3>Results: twenty-five ninth, 2.7 repeating where the 7 is repeating......</h3>

<h3>Hope this helps</h3><h3>Good luck ✅</h3>

8 0
2 years ago
Suppose a researcher compiled a data set consisting of the following variables for a sample of 100 retired men. For each variabl
kondaur [170]

Answer:

a) Discrete Variable

b) Discrete Variable

c) Discrete Variable

d) Continuous Variable

Step-by-step explanation:

We have to identify the given variable as discrete r continuous.

Discrete Variables:

  • They are expressed in whole numbers.
  • They are counted not measured.
  • They cannot take any value within an interval.

Continuous Variables:

  • They are expressed in decimal numbers.
  • They are measured not counted.
  • They cannot take any value within an interval.

a) The number of countries ever visited

Since number of countries will always be expressed in whole numbers and not decimals. Also, they will always be counted and not measured. Thus, it is a discrete variable.

b) The number of sons

Since number of sons will always be expressed in whole numbers and not decimals. Also, they will always be counted and not measured. Thus, it is a discrete variable.

c) Shoe size

Shoe size are expressed in whole number. The underlying measure is length of feet which is a continuous variable but shoe size are always given in whole number. Thus, they cannot take any value within an interval. Thus, it is a discrete variable.

d) Body temperature

Body temperature can be expressed in decimal. A Body temperature of 42.5 makes sense. Thus, they can take any value within an interval. Also, it is measured not counted. Thus, it is a discrete variable.

8 0
3 years ago
Rewrite the system of linear equations as a matrix equation AX = B.
iren2701 [21]

Answer:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

Step-by-step explanation:

Let's find the answer.

Because we have 3 equations and 3 variables (x1, x2, x3) a 3x3 matrix (A) can be constructed by using their respectively coefficients.

Equations:

Eq. 1 : x1 + 2x2 + 5x3 = 5

Eq. 2 : x1 + x2 + x3 = 6

E1. 3 : 4x1 + 6x2 + 5x3 = 7

Coefficients for x1 ; x2 ; x3

From eq. 1 : 1 ; 2 ; 5

From eq. 2 : 1 ; 1 ; 1

From eq. 3 : 4 ; 6 ; 5

So matrix A is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]

And the vector of vriables (X) is:

\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]

Now we can find the resulting vector (B) using the 'resulting values' from each equation:

\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

In conclusion, AX=B is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

7 0
4 years ago
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