Question

Find the equation of a circle centered on the origin going through the point (-5,3)

Answer 1

The given center and point on the circle of (0,0) and (-5, 3), respectively

gives the equation of the circle as $x^{2} +y^{2} =\sqrt{34}$.

The general form of the equation of the circle is presented as follows

(x - h)² + (y - k)² = r²

Where,(h, k) is the center of the circle and r is the radius of the circle

Here (h, k) is centered about the origin and the radius of the circle

Radius of the circle = √[(-5-0)² + (3-0)²]

= √(25+9)

=√34.

The equation of a circle centered on the origin going through the point (-5,3)

$x^{2} +y^{2} =\sqrt{34}$

Learn more about the equation of a circle brainly.com/question/502872

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