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1 year ago

1. One liter is equal to 1,000 milliliters. How many liters are equal to 18,045 milliliters?

Mathematics

1 answer:

aksik [14]1 year ago

4 0

Answer:

18.045

Step-by-step explanation:

because you will have 18liters and because of 045 you would let it stay the same and instead of a coma you would put a period.

hop this helps

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Solve the system of equations using the linear combination method {5p-3q=-39 -2p-3q=3

VikaD [51]

Answer:

p=-6

q=3

Step-by-step explanation:

5p-3q=-39

-2p-3q=3

Multiply the second equation by -1

2p +3q = -3

Add the first equation and the modified second equation

5p-3q=-39

2p +3q = -3

---------------------

7p = -42

Divide by 7

7p/7 = -42/7

p = -6

Now we can find q

2p +3q = -3

2(-6) +3q = -3

-12 +3q = -3

Add 12 to each side

-12+12 +3q = -3+12

3q = 9

Divide by 3

3q/3 = 9/3

q=3

6 0

2 years ago

Read 2 more answers

A set of equations is given below:

Novay_Z [31]

These would have infinite solutions because this is a slope-intercept equation. Since you are provided with the y-intercept in both, you can put anything in for the slope and it will work.

Hope this helps!

8 0

3 years ago

Would it still be 3.19? Because you don't need to round to 3.20 because 3.192 <--- the 2 won't do anything.. If it's 5 or hig

Leviafan [203]

Yes, remember this 4 or less let it rest, 5 or more let it soar.

7 0

3 years ago

According to a study conducted by the Gallup Organization, the the proportion of Americans who are afraid to fly is 0.10. A rand

notsponge [240]

Answer: 0.1457

Step-by-step explanation:

Let p be the population proportion.

Given: The proportion of Americans who are afraid to fly is 0.10.

i.e. p= 0.10

Sample size : n= 1100

Sample proportion of Americans who are afraid to fly = $\hat{p}=\dfrac{121}{1100}=0.11$

We assume that the population is normally distributed

Now, the probability that the sample proportion is more than 0.11:

$P(\hat{p}>0.11)=P(\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}>\dfrac{0.11-0.10}{\sqrt{\dfrac{0.10(0.90)}{1100}}})\\\\=P(z>\dfrac{0.01}{0.0090453})\ \ \ [\because z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}} ]\\\\=P(z>1.1055)\\\\=1-P(z\leq1.055)\\\\=1-0.8543=0.1457\ \ \ [\text{using z-table}]$

Hence, the probability that the sample proportion is more than 0.11 = 0.1457

3 0

3 years ago

Sally must have at least $200 in her savings account to avoid a

xxMikexx [17]

Answer:

675$

Step-by-step explanation:

got it right

7 0

2 years ago