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denis23 [38]
2 years ago
7

Many programmers think object-oriented programming is a superior approach to procedural programming. Others think it adds a leve

l of complexity that is not needed in many scenarios. Find and summarize arguments on both sides. With which side do you agree
Computers and Technology
1 answer:
fgiga [73]2 years ago
4 0

I agree with the programmers who think object-oriented programming is a superior approach to procedural programming.

<h3>Why is OOP better than procedural programming?</h3>

In terms of Security, Object-oriented programming is said to have more of a secure based than procedural programming, due to the level of abstraction or that is due to data hiding property.

Note that  It hinders the access of data to any member functions of the same class and one cannot see a thing like that such as data hiding in the procedural programming framework.

Learn more about object-oriented programming  from

brainly.com/question/12342989

#SPJ1

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BigorU [14]

Answer:

Option D is correct.

Explanation:

Option D is correct because  when the condition  if (list[j] < temp) is tested it only gets true when element in list[] array at <em>jth</em> position is less than the value in <em>temp</em> and after that it increments the value of c by this statement: c++ and so c is incremented from 0 to as much times as much elements in list[] are lesser than temp.

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4 years ago
Read 2 more answers
What are the inputs and outputs of the app "Spotify"?
Anastasy [175]

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Hope this helps.

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6 0
3 years ago
Write the definition of a function named quadratic that receives three double parameters a, b, c. If the value of a is 0 then th
VMariaS [17]

Answer:

#include <iostream>

#include <cmath>

using namespace std;

//initialize function quadratic

void quadratic(double, double, double);

int main() {

   //declare double variables a, b and c

   double a,b,c;

   //take input from user

   cin>>a>>b>>c;

   //call function quadratic

   quadratic(a,b,c);

return 0;

}

void quadratic(double a, double b, double  c){

   double root,n;

   //check if variable a is equal to zero

   if(a==0){

       cout<<"no solution for a=0"<<endl;

       return;

   }

   //check if b squared - 4ac is less than zero

   else

   if(((b*b)-(4*a*c))<0){

       cout<<"no real solutions"<<endl;

       return;

   }

   //print the largest root if the above conditions are not satisfied

   else{

       n=((b*b)-(4*a*c));

       root=(-b + sqrt(n)) / (2*a);

       cout<<"Largest root is:"<<root<<endl;

   }

   return ;

}

Explanation:

Read three double variables a, b and c from the user and pass it to the function quadratic. Check if the value of variable a is equal to zero. If true, print "no solution for a=0". If this condition is false, check if b squared - 4ac is less than zero. If true, print "no real solutions". If this condition is also false, calculate the largest solution using the following formula:

largest root = (-b + square root of (b squared - 4ac)) / (2*a)

Input 1:

2 5 3

Output 2:

Largest root is:-1

Input 2:

5 6 1

Output 2:

Largest root is:-0.2

5 0
4 years ago
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ipn [44]

Answer:

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7 0
3 years ago
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zlopas [31]

Answer:

b. channels

Explanation:

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5 0
4 years ago
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