No you would click save or save as
The best scenario is when a program suffers from frequent
page faults. In the situations when a kernel thread experiences a page fault,
another kernel thread can be switched in; something a single-threaded process
will not be capable of doing. Another best circumstance is when a program has
to wait for other systems events.
Answer:
public static void removeInRange(List<Integer> list, int value, int start, int end) {
for (int i = end - 1; i >= start; i--) {
if (list.get(i) == value) {
list.remove(i);
}
}
System.out.println(list);
}
Explanation:
- Create a method named <em>removeInRange</em> that takes four parameters, a list, an integer number, a starting index and an ending index
- Inside the method, initialize a <u>for loop</u> that iterates between starting index and ending index
- If any number between these ranges is equal to the given <em>value</em>, then remove that value from the list, using <u>remove</u> method
- When the loop is done, print the new list
If what I found is correct it would be C, all charts... If not that then it would be B.
