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4 years ago

What is the value of a+1/a? when 5+5/a=10

Mathematics

1 answer:

GenaCL600 [577]4 years ago

6 0

Answer:

I think 20 but i may of done my math wrong

Step-by-step explanation:

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Adam has 16.45 kg of flour,and he uses 6.4 kg to make hot cross buns. The remaining flour is exactly enough to make 15 batches o

ivolga24 [154]

0.67 kg of flour will be in each batch of scones

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3 years ago

The sum of two numbers times a third number is equal to the sum of each addend times the third number

Volgvan

Answer:

Distributive property of multiplication

Step-by-step explanation:

(6+3)*4 = 6*4 + 3*4

9*4 =36 24+12 = 36

3 0

4 years ago

XLCDLXVI in actual numbers

tatuchka [14]

Your answer will be 406 hope this helps

7 0

4 years ago

Dimitri is helping to plan the school talent show. Each performer for the talent show has 7 minutes for his or her performance,

Kaylis [27]

15 performances can be accommodated

<em><u>Solution:</u></em>

Given that,

Each performer for the talent show has 7 minutes for his or her performance

The introduction for the talent show is 25 minutes long

The entire show including the introduction, will last 130 minutes

Thus the remaining time for performances is:

Performance time = 130 minutes - 25 minutes

Performance time = 105 minutes

To find, the number of performances, divide the 105 by 7 minutes

$Number\ of\ performances = \frac{105}{7} = 15$

Thus 15 performances can be accommodated

5 0

4 years ago

Hi! I've tried this problem a couple times but am still stumped :( Can you help?!

aniked [119]

ANSWER:

$X\text{ = }\begin{bmatrix}{12} & {-4} & {-2} \\ {-8} & {-13} & {8} \\ {8} & {15} & {18}\end{bmatrix}$

EXPLANATION:

Given:

$U\text{ = }\begin{bmatrix}{1} & {3} & {-5} \\ {2} & {14} & {11} \\ {-8} & {0} & {5}\end{bmatrix}\text{ V =}\begin{bmatrix}{13} & {1} & {-7} \\ {-6} & {1} & {9} \\ {0} & {15} & {23}\end{bmatrix}$

Since U and V are Matrices with equal dimensions(3 x 3 matrix), and

X + U = V.

To solve for X, we have:

X = V - U

$\begin{gathered} X\text{ = V - U} \\ X\text{ = }\begin{bmatrix}{13-1} & {-1-3} & {-7-(-5)} \\ {-6-2} & {1-14} & {19-11} \\ {0-(-8)} & {15-0} & {23-5}\end{bmatrix}=\text{ }\begin{bmatrix}{12} & {-4} & {-2} \\ {-8} & {-13} & {8} \\ {8} & {15} & {18}\end{bmatrix} \end{gathered}$ $X\text{ = }\begin{bmatrix}{12} & {-4} & {-2} \\ {-8} & {-13} & {8} \\ {8} & {15} & {18}\end{bmatrix}$

6 0

1 year ago