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Anettt [7]
2 years ago
11

URGENT!!

Mathematics
2 answers:
Lapatulllka [165]2 years ago
3 0

Answer:

f[g(4)] = 4

Step-by-step explanation:

Given table:

\begin{array}{| c | c | c | c | c | c |}\cline{1-6} x & -6 & -4 & 1 & 3 & 4\\\cline{1-6} f(x) & 4 & -1 & -6 & 1 & 3 \\\cline{1-6} g(x) & 1 & 4 & 3 & -4 & -6 \\\cline{1-6}\end{array}

f[g(4)] is a composite function.

When calculating <u>composite functions</u>, always work from inside the brackets out.

Begin with g(4):  g(4) is the value of function g(x) when x = 4.

From inspection of the given table, g(4) = -6

Therefore, f[g(4)] = f(-6)

f(-6) is the value of function f(x) when x = -6.

From inspection of the given table, f(-6) = 4

Therefore, f[g(4)] = 4

Alla [95]2 years ago
3 0

As we can see

  • g(4)=-6

So

  • f(g(4))
  • f(-6)
  • 4
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The cost of 4 belts and 5 ties is $247. Each time costs 3 times as much as a belt. What us the total cost of 1 belt and 1 tie
Makovka662 [10]

Answer:

The total cost of 1 belt and 1 tie is $13 and $39 respectively.

Step-by-step explanation:

Given that,

The cost of 4 belts and 5 ties is $247.

Each tie costs 3 times as much as a belt.

Let the cost of a belt is x and that of a tie is y.

ATQ,

4x + 5y = 247 ...(1)

y = 3x ....(2)

Put the value of y from equation (2) in equation (1)

4x + 5(3x) = 247

4x + 15x = 247

19x = 247

x = 13

Put the value in equation (2)

y = 3x

= 3(13)

= 39

So, the total cost of 1 belt and 1 tie is $13 and $39 respectively.

5 0
3 years ago
The number of failures of a testing instrument from contamination particles on the product is a Poisson random variable with a m
Mazyrski [523]

Answer:

The probability that the instrument does not fail in an 8-hour shift is P(X=0) \approx 0.8659

The probability of at least 1 failure in a 24-hour day is P(X\geq 1 )\approx 0.3508

Step-by-step explanation:

The probability distribution of a Poisson random variable X representing the number of successes occurring in a given time interval or a specified region of space is given by the formula:

P(X)=\frac{e^{-\mu}\mu^x}{x!}

Let X be the number of failures of a testing instrument.

We know that the mean \mu = 0.018 failures per hour.

(a) To find the probability that the instrument does not fail in an 8-hour shift, you need to:

For an 8-hour shift, the mean is \mu=8\cdot 0.018=0.144

P(X=0)=\frac{e^{-0.144}0.144^0}{0!}\\\\P(X=0) \approx 0.8659

(b) To find the probability of at least 1 failure in a 24-hour day, you need to:

For a 24-hour day, the mean is \mu=24\cdot 0.018=0.432

P(X\geq 1 )=1-P(X=0)\\\\P(X\geq 1 )=1-\frac{e^{-0.432}0.432^0}{0!}\\\\P(X\geq 1 )\approx 0.3508

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3 years ago
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Sergio039 [100]

The limit of the expression as x approaches -3 is -24

<h3>How to determine the limit of the expression?</h3>

The expression is given as:

x^3 + 3x^2 + 4x - 12

As x approaches -3.

The limit expression becomes

\lim_{x \to -3} x^3 + 3x^2 + 4x - 12

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Read more about limit expressions at:

brainly.com/question/16176002

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