Answer:
The second: 
Step-by-step explanation:
![f (x) =4x^2+6x-3\\\\f (x) =4(x^2+\frac64x]-3\\\\f (x) =4[x^2+2\cdot x\cdot\frac34+(\frac34)^2-(\frac34)^2]-3\\\\f (x) =4[(x+\frac34)^2-(\frac34)^2]-3\\\\f (x) =4(x+\frac34)^2-4(\frac34)^2-3\\\\f (x) =4(x+\frac34)^2-\frac94-\frac{12}4\\\\\underline{f (x) =4(x+\frac34)^2-\frac{21}4}](https://tex.z-dn.net/?f=f%20%28x%29%20%3D4x%5E2%2B6x-3%5C%5C%5C%5Cf%20%28x%29%20%3D4%28x%5E2%2B%5Cfrac64x%5D-3%5C%5C%5C%5Cf%20%28x%29%20%3D4%5Bx%5E2%2B2%5Ccdot%20x%5Ccdot%5Cfrac34%2B%28%5Cfrac34%29%5E2-%28%5Cfrac34%29%5E2%5D-3%5C%5C%5C%5Cf%20%28x%29%20%3D4%5B%28x%2B%5Cfrac34%29%5E2-%28%5Cfrac34%29%5E2%5D-3%5C%5C%5C%5Cf%20%28x%29%20%3D4%28x%2B%5Cfrac34%29%5E2-4%28%5Cfrac34%29%5E2-3%5C%5C%5C%5Cf%20%28x%29%20%3D4%28x%2B%5Cfrac34%29%5E2-%5Cfrac94-%5Cfrac%7B12%7D4%5C%5C%5C%5C%5Cunderline%7Bf%20%28x%29%20%3D4%28x%2B%5Cfrac34%29%5E2-%5Cfrac%7B21%7D4%7D)
The greatest common factor is 8. So your answer would be: 8(5j - 2) because 8 x 5j= 40j and 8 x 2= 16
To find the area you need to multiply.
AB + CD = BC + DA
<span>Where A, B, C, and D are points on the quad, and AB is the length of the line A to B, etc. </span>
<span>Since you know three sides, you can easily solve for the fourth. </span>