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SVETLANKA909090 [29]
3 years ago
15

Find the gradient and y intercept of 3x+4y=5

Mathematics
1 answer:
noname [10]3 years ago
3 0

Answer:

gradient = - \frac{3}{4} , y- intercept = \frac{5}{4}

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

3x + 4y = 5 ( subtract 3x from both sides )

4y = - 3x + 5 ( divide terms by 4 )

y = - \frac{3}{4} x + \frac{5}{4} ← in slope- intercept form

with slope m = - \frac{3}{4} and y- intercept c = \frac{5}{4}

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Answer:

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Step-by-step explanation:

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2 years ago
Findℒ{f(t)}by first using a trigonometric identity. (Write your answer as a function of s.)f(t) = 12 cost −π6
allsm [11]

Answer:

L(f(t)) = \dfrac{6}{S^2+1} [\sqrt{3} \ S +1 ]

Step-by-step explanation:

Given that:

f(t)  = 12 cos (t- \dfrac{\pi}{6})

recall that:

cos (A-B) = cos AcosB + sin A sin B

∴

f(t) = 12 [cos\  t \  cos \dfrac{\pi}{6}+ sin \ t  \ sin \dfrac{\pi}{6}]

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f(t) = 6 \sqrt{3} \ cos \ (t) + 6 \ sin \ (t)

L(f(t)) = L ( 6 \sqrt{3} \ cos \ (t) + 6 \ sin \ (t) ]

L(f(t)) = 6 \sqrt{3} \ L [cos \ (t) ] + 6\ L [ sin \ (t) ]

L(f(t)) = 6 \sqrt{3}  \dfrac{S}{S^2 + 1^2}+ 6 \dfrac{1}{S^2 +1^2}

L(f(t)) = \dfrac{6 \sqrt{3} +6 }{S^2+1}

L(f(t)) = \dfrac{6( \sqrt{3} \ S +1 }{S^2+1}

L(f(t)) = \dfrac{6}{S^2+1} [\sqrt{3} \ S +1 ]

7 0
3 years ago
Two given angles cannot be both..
PolarNik [594]
The right answer is congruent and complementary because they both are different from each other and different causes
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3 years ago
What is the answer to -(7-4x)=9
Veseljchak [2.6K]

Answer:

x = 4

Step-by-step explanation:

change the signs on both sides of the equation

7-4x= - 9

move constant to the right side and change its sign

- 4x = - 9 - 7

-4x= - 16

divide both sides of the equation by -4

x = 4

7 0
3 years ago
OK Brainly is the correct answer no leaks
PolarNik [594]

Answer:

4

Step-by-step explanation:

1+9+5+0+8+1+7+4+1=36

then divide by the total number of digits which is 9

36/9=4

7 0
3 years ago
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