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k0ka [10]
2 years ago
5

X: -1/2-6(x-2)pls i need a result

Mathematics
1 answer:
Rufina [12.5K]2 years ago
8 0

Answer:

15

Step-by-step explanation:

First, we can plug -1/2 into the equation and get -6(-1/2 -2). Then, we can convert -2 into a fraction to get -4/2. If we subtract -4/2 from -1/2, we get -6(-5/2). We then multiply this and get 30/2 which simplifies to 15

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Prove by mathematical induction that 1+2+3+...+n= n(n+1)/2 please can someone help me with this ASAP. Thanks​
Iteru [2.4K]

Let

P(n):\ 1+2+\ldots+n = \dfrac{n(n+1)}{2}

In order to prove this by induction, we first need to prove the base case, i.e. prove that P(1) is true:

P(1):\ 1 = \dfrac{1\cdot 2}{2}=1

So, the base case is ok. Now, we need to assume P(n) and prove P(n+1).

P(n+1) states that

P(n+1):\ 1+2+\ldots+n+(n+1) = \dfrac{(n+1)(n+2)}{2}=\dfrac{n^2+3n+2}{2}

Since we're assuming P(n), we can substitute the sum of the first n terms with their expression:

\underbrace{1+2+\ldots+n}_{P(n)}+n+1 = \dfrac{n(n+1)}{2}+n+1=\dfrac{n(n+1)+2n+2}{2}=\dfrac{n^2+3n+2}{2}

Which terminates the proof, since we showed that

P(n+1):\ 1+2+\ldots+n+(n+1) =\dfrac{n^2+3n+2}{2}

as required

4 0
3 years ago
I need help. I’ve been stuck
solniwko [45]
Ok RYU? Isn’t it 110*?
3 0
3 years ago
The coordinates of point A on a coordinate grid are (−2, −3). Point A is reflected across the y-axis to obtain point B and acros
amid [387]

Answer:

B) B(2,-3) and C(-2,3)

Step-by-step explanation:

The given point A, has coordinates (-2,-3).

When point A(-2,-3) is reflected over the y-axis to obtain point B, then the coordinates of B is obtained by negating the x-coordinate of A.

Therefore B will have coordinates (2,-3).

 When point A(-2,-3) is reflected over the x-axis to obtain point C, then the coordinates of C is obtained by negating the y-coordinate of A.

Hence the coordinates of C are (-2,3)

3 0
3 years ago
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sveta [45]

All of them are, except ' π ' (pi) ... which gives you an idea of why
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Here's a useful factoid regarding the other numbers on the list:
-- <em>ANY</em> number that you can write down on paper, <u>completely</u>,
using digits, is a rational number.


4 0
3 years ago
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