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Lapatulllka [165]
3 years ago
12

If f(x) = 4x² – 3x + 8, then f(-2) =

Mathematics
1 answer:
Citrus2011 [14]3 years ago
7 0

Answer: 30

Step-by-step explanation:

16+6+18

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Plss help me plsss!!​
grin007 [14]

Answer:

  • 20 units

Step-by-step explanation:

The first part is already solved.

<u>We got the scale factor </u>

  • k = 4

<u>Use this to find the missing side:</u>

  • MN = k*YZ
  • MN = 4*5 = 20
3 0
3 years ago
Read 2 more answers
5) In a certain supermarket, a sample of 60 customers who used a self-service checkout lane averaged 5.2 minutes of checkout tim
Ne4ueva [31]

Answer:

\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643

S_p=2.940

t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751

df=60+72-2=130

p_v =P(t_{130}

Assuming a significance level of \alpha=0.05 we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

Step-by-step explanation:

Data given

Our notation on this case :

n_1 =60 represent the sample size for people who used a self service

n_2 =72 represent the sample size for people who used a cashier

\bar X_1 =5.2 represent the sample mean for people who used a self service

\bar X_2 =6.1 represent the sample mean people who used a cashier

s_1=3.1 represent the sample standard deviation for people who used a self service

s_2=2.8 represent the sample standard deviation for people who used a cashier

Assumptions

When we have two independent samples from two normal distributions with equal variances we are assuming that  

\sigma^2_1 =\sigma^2_2 =\sigma^2

The statistic is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

And t follows a t distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:

\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

System of hypothesis

Null hypothesis: \mu_1 \geq \mu_2

Alternative hypothesis: \mu_1 < \mu_2

This system is equivalent to:

Null hypothesis: \mu_1 - \mu_2 \geq 0

Alternative hypothesis: \mu_1 -\mu_2 < 0

We can find the pooled variance:

\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643

And the deviation would be just the square root of the variance:

S_p=2.940

The statistic is given by:

t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751

The degrees of freedom are given by:

df=60+72-2=130

And now we can calculate the p value with:

p_v =P(t_{130}

Assuming a significance level of \alpha=0.05 we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

5 0
3 years ago
Write the equation of the line with a slope of 3/2 that contains the point (-2,-4) .
VARVARA [1.3K]

Answer:

y= 3/2x- 4

Step-by-step explanation:

3/2 = mx

b= -4

y=mx+b

8 0
3 years ago
Divide.<br>(3x4 - 3x2 - 6x - 10) = (x - 2)​
alekssr [168]

Answer:

3x^3 + 6x^2 + 15x + 36 + 62 / 3x^4 +3x^2 +6x + 10

Step-by-step explanation:

Use Syenthetic Division

4 0
3 years ago
Gemma and Leah are both jewelry makers. Gemma made 106 beaded necklaces. Leah made 39 more necklaces than Gemma.
timofeeve [1]

Answer:

Gemma made $34 more than Leah.

Step-by-step explanation:

Gemma made number of beaded necklaces = 106

Leah made 39 more necklaces than Gemma.

Leah made number of beaded necklaces  = 106 + 39 = 145

a. There are 104 beads on each necklace.

The total number of beads used altogether

= (106 × 104) + (145 × 104)

= 11,024 + 15,080

= 26,104

b. Gemma sold her 106 necklaces for = $14

Total price of her necklaces = 106 × 14

                                               = $1,484

Leah sold her 145 necklaces for = $10

Total price of her necklaces = 145 × 10

                                               = $1,450

Difference in Gemma and Leah's amount = 1484 - 1450 = $34.00

Therefore, Gemma made $34.00 more money than Leah.

6 0
3 years ago
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