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densk [106]
2 years ago
7

Patel is solving 8x2 + 16x + 3 = 0. Which steps could he use to solve the quadratic equation? Select three options. 8(x2 + 2x +

1) = –3 + 8 x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot x = –1 Plus or minus StartRoot StartFraction 4 Over 8 EndFraction EndRoot 8(x2 + 2x + 1) = 3 + 1 8(x2 + 2x) = –3
Mathematics
1 answer:
AnnyKZ [126]2 years ago
4 0

The options Patel has to solve the quadratic equation 8x² + 16x + 3 = 0 is x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot.

<h3>Quadratic equation</h3>

8x² + 16x + 3 = 0

8x² + 16x = -3

8(x² + 2x) = -3

  • Using completing the square

8(x² + 2x + 1) = -3 + 8

  • factorization

8(x² + 1) = 5

(x² + 1) = 5/8

  • Taking the square root of both sides

(x + 1) = ± √5/8

x = -1 ± √5/8

Therefore,

x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot

Learn more about quadratic equation:

brainly.com/question/1214333

#SPJ1

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Answer:

\sf x=2+\sqrt{6},\:x=2-\sqrt{6}

Explanation:

\sf y = x^2 -4x

given that y = 2

\sf x^2 -4x = 2

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using quadratic formula:

\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a}  \    \ \ when  \   ax^2 + bx + c = 0

\rightarrow \sf x_{1,\:2}=\dfrac{-\left(-4\right)\pm \sqrt{\left(-4\right)^2-4\cdot \:1\cdot \left(-2\right)}}{2\cdot \:1}

\rightarrow \sf x_1=\dfrac{-\left(-4\right)+2\sqrt{6}}{2\cdot \:1},\:x_2=\dfrac{-\left(-4\right)-2\sqrt{6}}{2\cdot \:1}

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in decimals:

\rightarrow \sf x=4.45 , \ -0.45

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2 years ago
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