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2 years ago

I’m confused in the exponential

Mathematics

1 answer:

Anna [14]2 years ago

4 0

Answer:

this mean in case of multiplying exponents with same base you should add the exponent and keep base same.

example:

${6}^{4} \times {6}^{5 } = {6}^{4 + 5} \\ = {6}^{9}$

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I need to solve for x

umka21 [38]

Answer:

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3 years ago

Read 2 more answers

Match each pair of points with the coordinate that will make a right triangle with its hypotenuse along the graph shown.

MrRa [10]

1 is B
2 is C
3 is A
4 is E

It's a simple question if you use the graph. I recommend you plot the points, so hopefull you can see how i got the answers.

6 0

3 years ago

Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li

krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

$A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years$

First, let us calculate the decay constant (k)

$75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036$

Next, let us calculate the half-life as follows:

$\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2} \approx 669\ years$

Therefore the half-life is between 600 and 700 years

5 0

3 years ago

Explain how g is 62 degrees using angle theorem. Ex supplementary angle theorem, ASTT. Etc

bazaltina [42]

Answer:

The exterior angle is 35° + 62° = 97°

And 97° > 35°

And 97° > 62°

Step-by-step explanation:

6 0

3 years ago

Given the functions j(x) = x2 + 3 and k(x) = x2 − x + 4, which operation results in a 2nd degree polynomial?

GrogVix [38]

Addition is the correct answer.

x^2 is the part where you get the second degree term. If you add x^2+x^2 you get 2x^2. If you subtract x^2-x^2 you get 0. If you multiply x^2*x^2 you get x^4, which is a fourth degree term

8 0

3 years ago