7 (6) + 14!!! And this needs to be 20 characters long so I’m adding this
Answer:
P.7500.00
Step-by-step explanation:
We are told that:
The ratio of Val's savings to Dan is 2:3 at first.
Now, Dan spent P3000.00 and Val's saving became 1⅓ more of that Dan's remaining savings.
Let's say the total amount of savings they had at first was x.
Thus;
Val had: 2x/5
Dan had: 3x/5
Now, Dan spent P3000.00.
So amount Dan has left = (3x/5) - 3000
We are told Val's savings is now 1⅓ = 4/3 times that of Dan's remaining savings
Thus; 2x/5 = (4/3)((3x/5) - 3000)
2x/5 = 12x/15 - 4000
Multiply through by 15 to get;
6x = 12x - (3000 × 15)
6x = 12x - 45000
Rearranging, we have;
12x - 6x = 45000
6x = 45000
x = 45000/6
x = P.7500
Answer:
Step-by-step explanation:
The function that could model this periodic phenomenon will be of the form
The tide varies between 3ft and 9ft, which means its amplitude 
is
and its midline 
is
.
Furthermore, since at 
the tide is at its lowest ( 3 feet ), we know that the trigonometric function we must use is 
.
The period of the full cycle is 14 hours, which means
giving us
With all of the values of the variables in place, the function modeling the situation now becomes
Answer:
-7 OR -9
Step-by-step explanation:
8-7 in the inside
Absolute value of 1 is 1
OR
8-9 in the inside for -1
Absolute value of -1 is 1
Absolute value signs makes everything positive
<span>a) Differentiate both sides of lnq − 3lnp + 0.003p=7 with respect to p, keeping in mind that q is a function of p and so using the Chain Rule to differentiate any functions of q:
(1/q)(dq/dp) − 3/p + 0.003 = 0
dq/dp = (3/p − 0.003)q.
So E(p) = dq/dp (p/q) = (3/p − 0.003)(q)(p/q) = (3/p − 0.003)p = 3 − 0.003p.
b) The revenue is pq.
Note that (d/dp) of pq = q + p dq/dp = q[1 + dq/dp (p/q)] = q(1 + E(p)), which is zero when E(p) = −1. Therefore, to maximize revenue, set E(p) = −1:
3 − 0.003p = −1
0.003p = 4
p = 4/0.003 = 4000/3 = 1333.33</span>
