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marusya05 [52]
1 year ago
8

A canadian goose and a Great blue heron took off in opposite directions. The goose flew at 20 mph, and the heron flew at 10 mph.

when they landed, they were 180 miles apart. Altogether, they flew for 14 hours. How long did each bird fly?
Mathematics
1 answer:
iris [78.8K]1 year ago
4 0

The Canadian goose flew for 4 hours and the Great blue heron flew for 10 hours

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Let a represent the time flown by the goose and b represent the time flown by the heron. Hence:

a + b = 14    (1)

Also:

20a + 10b = 180   (2)

From equation 1 and 2:

a = 4, b = 10

The Canadian goose flew for 4 hours and the Great blue heron flew for 10 hours

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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Also as the tangent is negative in the second quadrant theta can also be 135 degrees or - 225 degrees. 
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Urn A contains four white balls and five black balls. Urn B contains six white balls and three black balls. A ball is drawn from
Kamila [148]

Answer:

If the seond ball drawn was white, there is a 48.3% probability that the transferred ball was white.

Step-by-step explanation:

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

For this problem, we have:

What is the probability of the transfered ball being white, given that the second ball drawn was white.

P(B) is the probability that the ball transfered is white. The ball is transferred from urn A to urn B. Urn A contains four white balls and five black balls. So P(B) = \frac{4}{9} = 0.444

P(A/B) is the probability that the second ball drawn is white, given that a white ball was transferred. If a white ball was transferred, there will be 10 balls in Urn B, 7 of which are white. So P(A/B) = 0.7.

P(A) is the probability that the ball drawn for the second urn is white. There are two cases. Either a black ball is transfered(with probability \frac{5}{9} = 0.556) and then a white ball is drawn, with probability \frac{6}{10} = 0.6. Or we have P(A/B), with probability 0.444. So

P(A) = 0.444*0.7 + 0.556*0.6 = 0.644

Finally

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.444*0.7}{0.644} = 0.483

If the seond ball drawn was white, there is a 48.3% probability that the transferred ball was white.

5 0
2 years ago
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