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3 years ago

If Joel’s family starts with a full tank of gas, can they drive the car for 15 days without the warning light coming on?

Mathematics

1 answer:

vlada-n [284]3 years ago

8 0

Answer:

Yes they can drive for 15 days without the light

Step-by-step explanation:

If its 0.5 gass each day 0.5 gas ×15days that would be 7.5

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20×9×5 distributive property

Katena32 [7]

20times 9 times 5 is 900

8 0

2 years ago

Read 2 more answers

3. In the fig. AD = DC and AB = BC. Prove that ΔADB = ΔCDB<br>

xxMikexx [17]

Answer:

The two column proof is presented as follows;

The given parameters are;

$\overline {AD}$ = $\overline {DC}$ and $\overline {AB}$ = $\overline {BC}$

Statement ${}$ Reason

$\overline {AD}$ = $\overline {DC}$ and $\overline {AB}$ = $\overline {BC}$ ${}$ Given

$\overline {BD}$ ≅ $\overline {BD}$ ${}$ Reflexive property

$\overline {BD}$ = $\overline {BD}$ ${}$ By the definition of congruency

ΔADB ≅ ΔCDB ${}$ By Side-Side-Side (SSS) rule of congruency

ΔADB = ΔCDB ${}$ By the definition of congruency

If the three sides of one triangle are congruent to the corresponding three sides of another triangle, then both triangles are said to be congruent according to the SSS rule of congruency

Step-by-step explanation:

7 0

3 years ago

The resting heart rate for an adult horse should average about µ = 47 beats per minute with a (95% of data) range from 19 to 75

KatRina [158]

Answer:

a. 0.0582 = 5.82% probability that the heart rate is less than 25 beats per minute.

b. 0.1762 = 17.62% probability that the heart rate is greater than 60 beats per minute.

c. 0.7656 = 76.56% probability that the heart rate is between 25 and 60 beats per minute

Step-by-step explanation:

Empirical Rule:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean:

$\mu = 47$