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Paul [167]
1 year ago
10

What are the lengths of A ⁢ D ¯ , D ⁢ B ¯ , A ⁢ E ¯ , and E ⁢ C ¯ ? Measure and record them.

Mathematics
1 answer:
Natali5045456 [20]1 year ago
3 0

For this exercise, you could get the following lengths by using a scale (ruler):

  1. AD = 7.5 units.
  2. DB = 18.5 units.
  3. AE = 7.01 units.
  4. EC = 17.28 units.

<h3>What is a line segment?</h3>

A line segment can be defined as the part of a line in a geometric figure such as a triangle, that is bounded by two (2) distinct points and it typically has a fixed length.

In Geometry, a line segment can be measured by using the following measuring instruments:

  • A scale (ruler)
  • A divider

In this scenario, you're required to determine the lengths of the given line segments. However, the geometric figure wasn't included and as such an accurate answer can't provided.

For instance, you could get the following lengths by using a scale (ruler):

  1. AD = 7.5 units.
  2. DB = 18.5 units.
  3. AE = 7.01 units.
  4. EC = 17.28 units.

Read more on line segment here: brainly.com/question/18315903

#SPJ1

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3 years ago
Determine the first five iterates of f(x)=1.5x(1-x) for x0=0.8
kherson [118]
<span>f(x) = 1.5 x (1 - x)
f(0.8) = 1.5(0.8)(1 - 0.8) = 0.24
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3 0
3 years ago
Which list is in order from least to greatest? A) 9.4 * 10^-8, 9.25 * 10^-6, 2.5 * 10^3, 7* 10^3 B) 2.5 *10^3, 7 * 10^3, 9.25 *
vladimir1956 [14]

ANSWER

A) 9.4 * 10^-8, 9.25 * 10^-6, 2.5 * 10^3, 7* 10^3

EXPLANATION

The numbers are given in standard form.

The first criteria we will use to order them is the exponents.

The bigger the exponents the bigger the number.

The second criteria is that, if the exponents of any two numbers are the same, then we use the numbers multiplying the powers of 10 to order.

9.4 * 10^{-8}  \: <   \: 9.25 * 10^{-6} \:  <  \: 2.5 * 10^3 \:  <  \: 7* 10^3

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6 0
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Read 2 more answers
Determine the slope of the line that contains the points A(0, 2) and B(7,3). *
IgorC [24]

<h3><u>Given</u><u> </u><u>points</u><u>:</u><u>-</u></h3>
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We know that

{\boxed{\sf Slope_{(m)}=\dfrac {y_2-y_1}{x_2-x_1}}}

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\qquad\quad {:}\longrightarrow\tt m=\dfrac {3-2}{7-0}

\qquad\quad {:}\longrightarrow\tt m=\dfrac {1}{7}

\therefore \sf Slope\:of\:the\:line\:is\:\dfrac {1}{7}

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