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OLga [1]
2 years ago
15

What is the solution of the system of equations shown in the graph?

Mathematics
1 answer:
Rudiy272 years ago
3 0

Answer:

The solution of the system of equations shown in the graph is (2,0)

Step-by-step explanation:

It's easy

You just look for the point of intersections the lines make.

The point is on the number 2  on the x axis, and number 0 on the y axis. Therefore its (2,0).

Happy to help!

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What is the length of segment BC
Nastasia [14]
If you form a triangle with the points B and C as two of the points of the right angled triangle then you use Pythagoras to find the length of BC.

3^2+4^2=25
√25 = 5
7 0
2 years ago
Parabola passes through the points (0,5), (1,4), and (2,5). What function does the graph represent?
AfilCa [17]

Answer:

x^2 - 2x + 5 = 0.

Step-by-step explanation:

The (0, 5) is the point where the parabola passes through the y axis (where x = 0), so we can write the equation as

y = ax^2 + bx + 5   where a and b are constants to be found.

Also, since (1, 4) and (2, 5) are points on the curve, substituting, we have the system:

a(1)^2 + 1b + 5 = 4

a(2)^2 + 2b + 5 = 5

Simplify these 2 equations:

a  + b  =  -1  .................(1)

4a + 2b = 0..................(2)

Multiply the first equation by -2:

-2a - 2b = 2 .................(3)

Add (2) + (3):

2a = 2

a = 1.

Substitute a = 1 into (2):-

4*1 + 2b = 0

2b = -4

b = -2.

7 0
3 years ago
part 3. Find the value of the trig function indicated, use Pythagorean theorem to find the third side if you need it.​
Nat2105 [25]

Answer:  \bold{9)\ \sin \theta=\dfrac{1}{3}\qquad 10)\ \sin \theta = \dfrac{4}{5}\qquad 11)\ \cos \theta = \dfrac{\sqrt{11}}{6}\qquad 12)\ \tan \theta = \dfrac{17\sqrt2}{26}}

<u>Step-by-step explanation:</u>

Pythagorean Theorem is: a² + b² = c²   , <em>where "c" is the hypotenuse</em>

<em />

9)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{4}{12}\quad \rightarrow \large\boxed{\dfrac{1}{3}}

Note: 4² + (8√2)² = hypotenuse²   →   hypotenuse = 12

10)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{16}{20}\quad \rightarrow \large\boxed{\dfrac{4}{5}}

Note: 12² + opposite² = 20²   →   opposite = 16

11)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{\sqrt{11}}{6}\quad =\large\boxed{\dfrac{\sqrt{11}}{6}}

Note: adjacent² + 5² = 6²   →   adjacent = √11

12)\ \tan \theta=\dfrac{\text{side opposite of}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{17}{13\sqrt2}\quad =\large\boxed{\dfrac{17\sqrt2}{26}}

Note: adjacent² + 7² = (13√2)²   →   adjacent = 17

5 0
3 years ago
The approximate areas of Georgia and Washington, D.C. are listed below: Georgia: 1.54 x 10^5 square kilometers Washington, D.C.:
lubasha [3.4K]
Ok grated answers here
8 0
2 years ago
Instructions
Nat2105 [25]
541/2 square in I hope this helps
3 0
3 years ago
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