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Solnce55 [7]
2 years ago
5

Find the solution of a(-12 + a) = 0

Mathematics
1 answer:
butalik [34]2 years ago
7 0

Answer:

a=0, 12

Step-by-step explanation:

a=0 and –12+a=0===> a=12

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Suppose we have four integers, no two of which are congruent $\pmod 6$. Let $N$ be the product of the four integers. If $N$ is n
aalyn [17]

Answer:

4

Step-by-step explanation:

Given:

A, B, C, D have distinct positive values for mod 6

A (mod 6) = 1

B (mod 6) = 2

C (mod 6) = 4

D (mod 6) = 5

Each mod 6 value cannot be a zero since the product ABCD is not a multiple of 6.

Furthermore, in order that ABCD mod 6 > 0, we cannot  have a residue equal to 3, else the product with a residue 2 or 4 will make the product a multiple of 6.

Thus the only positive residues can only be 1,2,4,5

A*B*C*D  (mod 6) > 0  = 1*2*4*5 (mod 6) = 4

4 0
4 years ago
Which statements are true regarding the area of circles & sectors? Check all that apply.
Fynjy0 [20]

Answer:

4pi r

Step-by-step explanation:

7 0
3 years ago
(x+2)(x+7) Write in simplified form
patriot [66]

Answer:

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Step-by-step explanation:

x×(x+7)+2×(x+7)

x^2+7x+2x +14

x^2+9x+14

4 0
3 years ago
If you answer (making sense) and explain (so I can understand) you will be awarded! Please help ASAPA
Pavlova-9 [17]
What you are doing is called cross multiplication. You have to multiply the top of  the first fraction by the bottom of the second fraction. 1 x 378, which equals 378. Then you multiply the bottom of the first fraction by the top of the second fraction. 250 x X. 250x=378. You then have to solve for x or divide 378 by 250. The answer to 378 / 250 = 1.512. But the instructions want you to round to the nearest tenth and that is the first decimal place. Your answer is 1.5.
8 0
4 years ago
Factor 4x squared-35x+4
ANEK [815]
4x^2-35x+4\\\\a=4;\ b=-35;\ c=4\\\\\Delta=b^2-4ac\to\Delta=(-35)^2-4\cdot4\cdot4=1225-64=1161\\\\x=\frac{-b\pm\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{1161}=\sqrt{9\cdot129}=3\sqrt{129}\\\\x=\frac{-(-35)\pm3\sqrt{129}}{2\cdot4}=\frac{35\pm3\sqrt{129}}{8}\\\\4x^2-35x+4=4\left(x-\frac{35-3\sqrt{129}}{8}\right)\left(x-\frac{35+3\sqrt{129}}{8}\right)
8 0
3 years ago
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