Which table represents a linear function? Which quadratic function is represented by the graph?
1 answer:
The first table is a quadratic function while the second table is a linear function.
<h3>How to Interpret Function Tables?</h3>
1) For the first table, we have;
x y
0 5
1 0
2 -3
3 -4
4 -3
x = 2 and x = 4 have same value of y = -3 and as such it will be a Quadratic Function.
y = x² - 6x + 5
2) For the second table, we have;
x y
2 5
5 14
6 17
8 23
10 29
This table is a Linear function because slope is same and equal to 3 all through. Thus, the equation is y = 3x - 1
3) For the third table, we have;
x y
-3 8
-2 4
-1 2
0 1
1 0.5
This is an exponential function because equation can be modelled by;
y = 2⁻ˣ
Read more about Function Tables at; brainly.com/question/3632175
#SPJ1
You might be interested in
Answer:
We conclude that the true average percentage of Silicon Dioxide is smaller than 5.5.
Step-by-step explanation:
We are given that the desired percentage of Silicon Dioxide (SiO2) in a certain type of aluminous cement is 5.5.
16 independently obtained samples are analyzed and a sample mean of 5.25 was obtained. Suppose that the percentage of SiO2 in a sample is normally distributed with a sigma of 0.3.
Let = <u><em>true average percentage of Silicon Dioxide.</em></u>
So, Null Hypothesis, :
5.5 {means that the true average is greater than or equal to 5.5}
Alternate Hypothesis, :
< 5.5 {means that the true average is smaller than 5.5}
The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;
T.S. = ~ N(0,1)
where, = sample mean percentage of Silicon Dioxide = 5.25
σ = population standard deviation = 0.3
n = sample size = 16
So, <em><u>the test statistics</u></em> =
= -3.33
The value of z test statistics is -3.33.
<u>Now, the P-value of the test statistics is given by;</u>
P-value = P(Z < -3.33) = 1 - P(Z 3.33)
= 1 - 0.9996 = <u>0.0004</u>
Since, the P-value of the test statistics is less than the level of significance as 0.0004 < 0.01, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.
Therefore, we conclude that the true average percentage of Silicon Dioxide is smaller than 5.5.